Question in picture im not smart

Michael recorded the number of points his team scores for the first seven basketball games 64 5860 5256 62-54 which box plot cor

natka813 [3]

The correct option is fourth option

Explanations:

From the data, re-arranging in ascending order, the median of the data is 58.

The upper quartile is 62, while the lower quartile is 54

From the options, only the 4th options represent a box plot of median 58, upper quartile of 62 and lower quartile of 54. This makes it the correct option

8 0

1 year ago

24. identify the x- and y- intercepts of the function

UNO [17]

hope its help full thank u❤️❤️❤️

8 0

3 years ago

Suppose there are 8 boys and 7 girls in a classroom. If one student is chosen at random to run a errand. What is the probability

LUCKY_DIMON [66]

Answer:

47%

Step-by-step explanation:

There are 15 total students, so find the percentage of girls out of the total students: 7/15= .466, which is about 47%. To double check, you can do the boys and make sure it adds to 100%. 8/15= .533, which is about 53%. 47+53=100. So girls are 47% and boys are 53%

4 0

2 years ago

a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.

Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

$A_x=50cos(89.75)$ so

$A_x=.22$

$B_x=200cos(0)$ so

$B_x=200$ and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

$C_x=200$ (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

$A_y=50sin(89.75)$ so

$A_y=50$ (which I'm counting as 2 sig fig's)

$B_y=200sin(0)$ so

$B_y=0$ and we need to add those results together.

$C_y=50$

Now for the resultant magnitude:

$C_{mag}=\sqrt{(200)^2+(50)^2}$ and that gives us a final magnitude of

$C_{mag}=206$ m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

$tan^{-1}(\frac{50}{200})=14$

The girl is 206 meters from her starting point at an angle of 14 degrees

4 0

3 years ago

Racionaliza las siguientes expresiones: a) 1-√3/5√2 b) 3-√3/3+√3

Nostrana [21]

$a) \frac{1- \sqrt{3} }{5 \sqrt{2} } = \frac{\sqrt{2}- \sqrt{6} }{10} \\\\
b) \frac{3- \sqrt{3} }{3+\sqrt{3}} = \frac{3\sqrt{3}-3}{6} = \frac{3(\sqrt{3}-1)}{6} =\frac{\sqrt{3}-1}{2}.$

7 0

3 years ago