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ankoles [38]
3 years ago
9

Consider an algorithm that uses only assignment statements that replaces the quadruple (w, x, y, z) with (x, y, z, w). What is t

he minimum number of assignment statements needed?
Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer:

The minimum number of assignment statements needed is 5

Step-by-step explanation:

To write the algorithm, we apply the strategy of interchanging the values of variables in the assignment statements.

Assume "tmp" is the new variable, let assign tmp to w

The algorithm is:

Procedure exchange (w,x,y,z: integers)

 tmp := w

    w := x

     x := y

     y := z

     z := tmp

    return (w,x,y,z)

end

From the algorithm, it is obvious that there will be a minimum of 5 assignment statements needed.

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Using synthetic divison, what is the quotient of this expression? <br>2x^2+5x-7 over x-2​
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A. 2x + 9 + 11 over x - 2

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2x^2+5x-7 over x-2​

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helena needs 3.5 cups of flour per loaf of bread and 2.5 cups of flour per batch of muffins. she also needs 0.75 cup of sugar pe
tatuchka [14]

The <em><u>correct answer</u></em> is:

She can make 2 loaves of bread and 4 batches of muffins.

Explanation:

Let b represent bread and m represent muffins.

The equation for the amount of flour she needs is 3.5b+2.5m=17.

The equation for the amount of sugar she needs is 0.75b+0.75m=4.5.

To solve this, we will want to eliminate one of the variables. To do this, we will make the coefficients of one of the variables the same. If we multiply 2.5 by 0.3, we get 0.75; this is what we will do to the first equation:

\left \{ {{0.3(3.5b+2.5m=17)} \atop {0.75b+0.75m=4.5}} \right.  \\ \\\left \{ {{1.05b+0.75m=17} \atop {-(0.75b+0.75m=4.5)}} \right.  \\ \\0.3b=0.6 \\ \\\frac{0.3b}{0.3}=\frac{0.6}{0.3} \\ \\b=2

She can bake two loaves of bread.

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2.5m/2.5 = 10/2.5

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She can bake 4 batches of muffins.

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