Using synthetic divison, what is the quotient of this expression? 2x^2+5x-7 over x-2

Mathematics

1 answer:

a_sh-v [17]2 years ago

7 0

Answer:

A. 2x + 9 + 11 over x - 2

Step-by-step explanation:

2x^2+5x-7 over x-2

divide - 2x^2 + 5x - 7 over x - 2 = 2x + 9x - 7 over x - 2

= 2x + 9x - 7 over x - 2

divide - 9x - 7 over x - 2 = 9 + 11 over x - 2

= 2x + 9 + 11 over x - 2

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Answer:

F = 7: 16

Step-by-step explanation:

Equating 1 : x and 7:2

x = 2:7

Substituting x into the other equation we have

1: 16/7

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$\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \sin B=\frac{b \sin A}{a} \\ \\ \sin B=\frac{13 \sin 29^{\circ}}{7.2} \\ \\ \boxed{m\angle B =\arcsin \left(\frac{65\sin 29^{\circ}{36} \right), 180^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$

Considering the diagram. $\angle B$ is shown to be acute, so $\boxed{m\angle B=\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$ .

Angles in a triangle add to 180°, so $m\angle C= 151^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)$ .

Using the law of cosines,

$AB=\sqrt{13^2 + 7.2^2-2(13)(7.2)\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)} \\ \\ \boxed{AB=\sqrt{220.84-187.2\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)}}$