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Yuki888 [10]
3 years ago
13

What is the equation of the line in slope-intercept form?ASAP!!! Please

Mathematics
2 answers:
balu736 [363]3 years ago
6 0

Answer:

The equation is y=4/3x+4

Step-by-step explanation:


VikaD [51]3 years ago
5 0
You can use Rise over Run to figure out the slope. 4/3. Then we put it in slope intercept form, (y=mx+b) M= slope and B= Y-intercept (where the line touches the y axis) Y=4/3x+4
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The Print Shop provides copying services to the general public. The Print Shop has equipment which is capable of making 1,800 co
steposvetlana [31]

a) The financial analysis determining the acceptance of the special order is as follows:

Data and Financial Analysis:

Capacity of photocopier per hour = 1,800 copies

Practical capacity of equipment = 7 hours

Total copies in a day = 12,600 (1,800 x 7)

Steady demand per day = 10,000

Variable cost per copy = $0.22

Service price per copy = $0.25

Profit per copy = $0.03 ($0.25 - $0.22)

Normal profit based on steady demand of 10,000 = $300 ($0.03 x 10,000)

Profit based on maximum capacity of 12,600 = $378 ($0.03 x 12,600)

Price per copy for the special customer = $0.24

Profit per copy based on special price of $0.24 = $0.02 ($0.24 - $0.22)

Profit from special customer with 5,000 pages = $100 (5,000 x $0.02)

Profit from other probable customers = $228 (7,600 x $0.03)

Lost profit for accepting special order based on maximum capacity = $50 ($378 - $228 - $100)

Lost profit if order is <u>not accepted</u> and demand is only 10,000 copies = $78 ($378 - $300)

  • Therefore, the special order at $0.24 should be accepted.

b) The largest order from customer that the shop could accept = 5,000 + $50/$0.02

= 5,000 + 2,500

= 7,500 copies

Thus, if the customer orders 7,500 copies to be made, the shop can still realize a maximum profit of $378 by accepting orders for additional 5,100 (12,600 - $7,500) copies from others.

Learn more: brainly.com/question/22599880

7 0
2 years ago
Earning $80,000 a year. What is your monthly income?
aleksklad [387]
80,000 per year....there are 12 months in a year

80,000 / 12 = 6666.67 per month
6 0
3 years ago
Read 2 more answers
10/m+n<br> m=-2<br> n=-1<br> what is the answer
Nesterboy [21]

negative 3 and one third

5 0
2 years ago
Find the perimeter of the triangle shown using the Associative proprety. 4 1/2 in 5 1/2in 6 in
torisob [31]
So assumn that the measures given are the legnths of the sides
perimiter=side1+side2+side3
so
side1=4 and 1/2
side2=5 and 1/2
side3=6
subsitute
p=(4+1/2)+(5+1/2)+(6)
associative prpoerty says (a+b)+c=a+(b+c) (it deals with addiont with parenthasees)
p=4+1/2+5+1/2+6
p=4+5+1/2+1/2+6
p=9+1+6
p=10+6
p=16 inches
3 0
3 years ago
Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti
natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5

Simplifying:

f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

P(A) = \int_{5}^{15} = \frac{375}{t^4}

Integral of \frac{1}{t^4} = t^{-4} is \frac{t^{-3}}{-3} = -\frac{1}{3t^3}

Then

\int \frac{375}{t^4} dt = -\frac{125}{t^3}

Applying the limits, by the Fundamental Theorem of Calculus:

At t = 15, f(15) = -\frac{125}{15^3} = -\frac{1}{27}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

P(B) = \int_{5}^{10} = \frac{375}{t^4}

We already have the integral, so just apply the limits:

At t = 10, f(10) = -\frac{125}{10^3} = -\frac{1}{8}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0
3 years ago
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