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3 years ago

5

Need help on this !!!!!

1 answer:

Arisa [49]3 years ago

4 0

Answer:

17

Step-by-step explanation:

Remark

In this formation, the chords cut each other so that

Equation

(3x - 1) * 3 = 12*(x -2) Remove the brackets.

Solution

9x - 3 = 12x - 24 Add 24 to both sides.

9x - 3 + 24 = 12x - 24 + 24 Combine

9x + 21 = 12x Subtract 9x from both sides

9x - 9x +21 = 12x - 9x

21 = 3x Divide by 3

21/2 = 3x/3

7 = x

Find QR

QR = 12 + x - 2

QR = 10 + 7

QR = 17

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Which numbers are rational numbers that are not integers?<br><br> 0,4,-2,2/3,-1.8,16,3.2,-5/4

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3 years ago

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What two rational expressions sum to <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%2B2%7D%7Bx%5E%7B2%7D-9%2B8%20%7D" id="TexFor

bulgar [2K]

Answer:

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

Step-by-step explanation:

Given

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

Required

Fill in the gaps

Going by the given parameters, we have that

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

$x^2 - 9x + 8$ , when factorized is $(x-1)(x-8)$

Hence; the expression becomes

$\frac{4x+2}{(x-1)(x-8)} = \frac{A}{(x-8)(x-1)} + \frac{B}{(x-1)(x-8)}$

Combine Fractions

$\frac{4x+2}{(x-1)(x-8)} = \frac{A + B}{(x-8)(x-1)}$

Simplify the denominators

$4x + 2 = A + B$

By direct comparison

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$B = 2$

Hence, the complete expression is

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

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3 years ago

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