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lara31 [8.8K]
3 years ago
7

(3x – 5 – 7x2) – (–2 + 6x2 – 5x)

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

8x-13x²-3

Step-by-step explanation:

you first have to work with the negative sign and the brackets by multiplying the negative sign by everything in the second brackets

3x-5-7x²+2-6x²+5x

then group the like terms

3x+5x-7x²-6x²+2-5

8x-13x²-3

I hope this helps

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Una botella tenía agua hasta de su capacidad. Luego, se agregó litro de agua y la botella quedó llena. Si x representa la capaci
Elena L [17]

Responder:

3 / 4x + 1/2 = x

Explicación paso a paso:

Dado que:

Capacidad total = x

Volumen inicial = cierta fracción * capacidad total

Volumen adicional agregado para llenar = 1/2

Por eso,

Inicial. Volumen + volumen adicional = volumen total

De las opciones:

Un volumen inicial de 3 / 4x

Volumen adicional de 1/2

Volumen total = x

Sumar todo hace que la ecuación:

3 / 4x + 1/2 = x

x - 3 / 4x = 1/2

Por lo tanto, la ecuación correcta de la opción es: 3 / 4x + 1/2 = x

7 0
3 years ago
Operations with rational expressions
Scorpion4ik [409]

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

Solution:

Given expression:

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}

To solve the given expression:

First simplify: \frac{50-2 w^{2}}{3 w^{2}+9 w-30}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}

Cancel the common factor (w + 5).

                      $=-\frac{2(w-5)}{3(w-2)}

Now substitute this in the given expression.

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}

Multiply the fractions \frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}

Factor the denominator 3(w-2)(6 w-30) =18(w-2)(w-5)

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}                        

Cancel the common factor 2(w – 5).

                               $=-\frac{w^{2}+5 w-14}{9(w-2)}

Factor the numerator w^{2}+5 w-14=(w-2)(w+7)

                               $=-\frac{(w-2)(w+7)}{9(w-2)}

Cancel the common factor (w – 2).

                               $=-\frac{w+7}{9}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

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80% of x = 0.80x or 4x/5

Any fraction equivalent to 80/100 can be used to multiply x. You could also divide x by any equivalent to 5/4 or 1.25.

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The child’s physical density is being measured by the displacement method. A child of 50 pounds is placed in a tub filled
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ANSWER

1.05 g/cm³

EXPLANTION

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The following ratios form a proportion. 5/18 = 10/90 <br><br> True or False<br><br> 13 pts.
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Answer:

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Step-by-step explanation:

6 0
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