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2 years ago

What is the measurement 222.008 mm rounded off to four significant digits?

Chemistry

2 answers:

strojnjashka [21]2 years ago

7 0

222.008+eh=345.003 it is that

Novosadov [1.4K]2 years ago

6 0

That would be 222.0 mm to 4 sig figs

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The [α] of pure quinine, an antimalarial drug, is −165. If a solution contains 86% quinine and 14% of its enantiomer (ee = 72%),

ratelena [41]

Answer : The [α] for the solution is, -118.8

Explanation :

Enantiomeric excess : It is defined as the difference between the percentage major enantiomer and the percentage minor enantiomer.

Mathematically,

$\%\text{ Enantiomer excess}=\%\text{ Major enantiomer}-\%\text{ Minor enantiomer}$

Given:

% major enantiomer = 86 %

% minor enantiomer = 14 %

Putting values in above equation, we get:

$\%\text{ Enantiomer excess}=86\%-14\%=72\%$

$\text{ Enantiomer excess}=\frac{72}{100}=0.72$

Now we have to calculate the [α] for the solution.

$[\alpha]=\text{Enantiomer excess}\times [\alpha]_{Pure}$

$[\alpha]=0.72\times -165$

$[\alpha]=-118.8$

Thus, the [α] for the solution is, -118.8

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3 years ago

Calculate the amount of energy when water at 72 degrees c freezes completely at 0 degrees c

gtnhenbr [62]

Answer:

The amount of energy needed when water at 72 degrees c freezes completely at 0 degrees c is $6.37\times10^4$ Joules

Explanation:

$Q = m \times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

$Q_{1}=100 g \times 4.184 \frac{J}{g^{\circ} \mathrm{C}} \times\left(72^{\circ} \mathrm{C}-0^{\circ} \mathrm{C}\right)$

$Q_1$ =30125J

Q is the heat energy in Joules

c is the specific heat capacity (for water 1.0 cal/(g℃)) or 4.184 J/(g℃)

m is the mass of water

mass of water is assumed as 100 g (since not mentioned)

$Q_2$ is the heat energy required for the phase change

$Q_2$ =mass × heat of fusion

$\\$Q_{2}=100 g \times 336 \frac{J}{g}$\\\\$Q_{2}=33600 J$$

Total heat = $Q_1 + Q_2$

Total Heat = 30123J + 33600J

= 63725 J

= $6.37\times10^4$ Joules is the answer

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2 years ago

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nikdorinn [45]

Hi!

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With this in mind, the answer will be C.

Hopefully, this helps! =)

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