Answer:
a) Acidic buffer
b) No buffer
c) Acidic buffer
d) Basic buffer
e) Basic buffer
Explanation:
a) 75.0 mL of 0.10 M HF ; 55.0 mL of 0.15 M NaF
-Acidic buffer
Mixing of 75.0 mL of 0.10 HF and 55.0 mL of 0.15 mL NaF results in acidic buffer. HF/NaF is a buffer of weak acid and its conjugate base. F- is the conjugate base of acid,HF.
b.) 150.0 mL of 0.10 M HF ; 135.0 mL of 0.175 M HCl-No buffer
Mixing HF and HCl will not results in a buffer. Both are acids, and no conjugate base is present.
c.) 165.0 mL of 0.10 M HF ; 135.0 mL of 0.050 M KOH-Acidic buffer
HF reacts with KOH to form KF. F- is a conjujate base of HF. As volume and concentration of HF is more than KOH, therefore, HF will remain after reaction with KOH. HF/KF will be a buffer of weak acid and its conjugate base.
d.) 125.0 mL of 0.15 M CH3NH2 ; 120.0 mL of 0.25 M CH3NH3Cl -Basic buffer
CH3NH2/CH3NH3+ is a buffer of weak base and its conjugate acid.
e.) 105.0 mL of 0.15 M CH3NH2 ; 95.0 mL of 0.10 M HCl-Basic buffer
CH3NH2 is a weak base and HCl is a strong acid. CH3NH2 reacts with HCl to form its conjugate acid CH3NH3+. Volume and concentration of CH3NH2 is more as compared to HCl and hence, will remain in the soution after reactionf with HCl.
CH3NH3+/CH3NH2 is a buffer of weak base and its conjugate acid.
Photon is a packet of light energy. Both photon and electron contribute mostly to the quantum mechanics of the atom. Every particle in quantum mechanical model is explained as dual natured, that is has both particle and wave nature. Photons exhibit wave light properties like diffraction, interference, etc.,At the same time they exhibit particle properties like having a definite momentum and position. Similarly electrons and other microscopic particles exhibit both particle and wave nature.
Therefore, the correct answer is:
Both photons and electrons display particle and wave-like behaviour.
Answer:
32.1 × 10²³ formula units of CuCl₂
Explanation:
Given data:
Number of moles of CuCl₂ = 5.33 mol
Number of formula units of CuCl₂ = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
one mole of any substance contain 6.022 × 10²³ formula units thus,
5.33 moles of CuCl₂ = 5.33 ×6.022 × 10²³ formula units
32.1 × 10²³ formula units of CuCl₂
