The atmospheric pressure will be:
The pressure of the atmosphere resulting from the mercury column is 0.959 atm
What is atmospheric pressure?
The force that an object experiences from the weight of the air above it per unit area are known as atmospheric pressure.
Given: Height of mercury column = 729 mm Hg
To find: The pressure of the atmosphere
Calculation:
The atmospheric column resulting from the mercury column is calculated as follows:
1 atm =760 mm Hg
So, we can convert the 729 mm Hg to atm, and we get
Atmospheric pressure = 729 x 1 atm / 760 = 0.959 atm
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Answer:
D
Explanation:
31 / 2.8 = 11.0714286 L per mole of helium
3.5 / 4 = 0.875 moles
2.8 + 0.875 = 3.675 moles
11.0714286 x 3.675 = 40.6875 L
In a perfect world without air resistance, the top of the swing would have the most potential energy, but the least amount of kinetic energy. As the pendulum falls down, it gains more kinetic energy as it travels faster due to gravitational acceleration but loses more potential energy as it loses height. The total amount of energy in the system (the sum of kinetic and potential energy) stays the same.
Answer:
<h2>30.2 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
volume = final volume of water - initial volume of water
From the question
volume = 35.9 ml - 25.8 ml = 10.1 mL
We have
mass = 2.99 × 10.1 = 30.199 g
We have the final answer as
<h3>30.2 g</h3>
Hope this helps you
<u>Answer: </u>The mass of water produced is 44.28 g
<u>Explanation:</u>
We are given:
Volume of oxygen gas = 27.50 L
At STP conditions:
22.4 L of volume is occupied by 1 mole of a substance
27.50 L of oxygen gas will be occupied by = 
The chemical equation for the formation of water follows:

By the stoichiometry of the reaction:
If 1 mole of oxygen gas produces 2 moles of water
So, 1.23 moles of oxygen gas will produce =
of water
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
Molar mass of water = 18 g/mol
Plugging values in equation 1:

Hence, the mass of water produced is 44.28 g