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Nastasia [14]
2 years ago
5

SOMEONE HELP ON NUMBER 1

Mathematics
1 answer:
vredina [299]2 years ago
8 0

Answer:

It is most definitely D, The volume of a cone is one-third of the volume of a cylinder.

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Estimate the square root of 75.<br> a. 8.7<br> b. 4.2<br> c. 7.4<br> d. 9.5
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Answer: A.8.7

Step-by-step explanation:

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the weight of 100 females aged 15 to 20 years has a mean of 120 pounds and a variance of 36 pounds. how many of the students has
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3 years ago
A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored
dem82 [27]

Answer:

Mutually exclusive,

P(\text{Lemon-lime or orange})=\frac{2}{3}

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

P(\text{Lemon-lime})=\frac{1}{3}

Let us find probability of finding one orange drink.

P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

P(\text{Orange})=\frac{1}{3}

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

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3 years ago
The gcf of 42 and 70 is
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The gcf of 42 and 70 is 14
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2 years ago
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