Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
Step-by-step explanation:
16x > 2x - 3
Subtract 2x from both sides
14x > -3
Then divide; -3/14
((5x2)+5.5+(6x3)+6.5+(7x5)+(7.5x4)+(8x4))/20
137/20
= 6.85
Dilation because the sides will not be the same size as the original
Answer:

Step-by-step explanation:
Using the rule of exponents
×
=
, then
×
=
= 