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Svet_ta [14]
3 years ago
12

Log 10,000 = ?This is such a stupid question, sorry lol

Mathematics
2 answers:
Yuri [45]3 years ago
7 0

Answer:

=4

Step-by-step explanation:

Lyrx [107]3 years ago
6 0

Answer:

Log 10,000 = 4

hope it helps!

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Simplify this expression 3x^2 y^2/24x
maksim [4K]
The answer would be  (1/8) (xy ^ 2).
Equation: 
3x ^ 2 y ^ 2 / 24x

 =(3/24) (x ^ 2 y ^ 2 / x)
SO simplify it is
= (1/8) (xy ^ 2)

 
The simplified expression for this case is given by:
 
(1/8) (xy ^ 2)
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A total of 820 tickets were sold for the school play. they were either adult tickets or student tickets. there were 70 more stud
Assoli18 [71]
375 numbers of adult tickets were sold
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Use the graph to evaluate the step function at x=3
Sliva [168]

Answer:

f(3)=5 is the correct answer.

Step-by-step explanation:

The question is asking for a defined point at the coordinate x=3 so the answer would be 5.

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3 years ago
A study of the pricing accuracy of checkout scanners at a store found that one of every 20 items is priced incorrectly. On any g
GalinKa [24]

Answer:

a) There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) 20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) 22.62% probability that at least one of the five items is priced incorrectly by the scanner

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is priced correctly, or it is not. The probability of an item being priced incorrectly is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Five items selected.

This means that n = 5

One of 20 is priced incorrectly.

This means that p = \frac{1}{20} = 0.05

a) Assuming that this store sells thousands of items every day, which probability distribution would you use and why?

There are going to be at least 15 items both priced correctly, and incorrectly, which means that we can use the normal approximation to the binomial to solve the exercise in this supposed problem.

b) What is the probability that exactly one of the five items is priced incorrectly by the scanner?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.05)^{1}.(0.95)^{4} = 0.2036

20.36% probability that exactly one of the five items is priced incorrectly by the scanner

c) What is the probability that at least one of the five items is priced incorrectly by the scanner?

Either no items are priced incorrectly, or at least one is. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 0

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.05)^{0}.(0.95)^{5} = 0.7738

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7738 = 0.2262

22.62% probability that at least one of the five items is priced incorrectly by the scanner

5 0
2 years ago
Can someone help me on this ?
klio [65]
When y is 0
x is -2

When x is 0
y is -4

The slope is negative -4/2 which is also -2/1 which is -2
4 0
2 years ago
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