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Svet_ta [14]
3 years ago
12

Log 10,000 = ?This is such a stupid question, sorry lol

Mathematics
2 answers:
Yuri [45]3 years ago
7 0

Answer:

=4

Step-by-step explanation:

Lyrx [107]3 years ago
6 0

Answer:

Log 10,000 = 4

hope it helps!

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Use the grouping method to factor this polynomial completely.<br> 3x3 + 12x2 + 2x + 8
dezoksy [38]

Answer:

(3x^2 + 2)(x + 4).

Step-by-step explanation:

3x3 + 12x2 + 2x + 8

3x^2(x + 4) + 2(x + 4)   The  x + 4 is common to the 2 groups so we have:

(3x^2 + 2)(x + 4).

3 0
3 years ago
PLZ Help fast. It's Pre Calculus. This is the only day i get to spend time with my baby sister. please help fast. WILL MARK BRAI
Ivahew [28]
1) x³ + 2x² - x - 2                            2) 2x³ + 5x² - 8x - 20 = 0

x²(x + 2) - (x + 2)                                x²(2x + 5) - 4(2x + 5) = 0

(x + 2)(x² - 1)                                      (2x + 5)(x² - 4) = 0

(x + 2)(x - 1)(x + 1)                             x = -5/2, +-2

x = -2, 1, -1   << a is the answer.

hope that helps, God bless!
5 0
3 years ago
Read 2 more answers
(23q – 34) and (–16q – r)
pochemuha

Answer:

=−368q2−23qr+544q+34r

Step-by-step explanation:

7 0
3 years ago
) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection
RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

C_{(m,n)} = \frac{m!}{n!(m-n)!}

In this question, m = 18, n = 9. So the total number of possibilities is:

T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715

The probability is the number of desired possibilities divided by the number of total possibilities. So

P = \frac{715}{48620} = 0.015 = 1.5%

The probability the he or she will answer correctly is 1.5%

3 0
3 years ago
There is 28 kg 750 g of sugar in a sack. How many tins of 500 g sugar can be filled using the sugar in the sack?
vovangra [49]

Answer:

Step-by-step explanation:

28 kg + 750 g = 28*1000 + 750

                          28000 + 750

                       = 28750 g

Number of sack = Total quantity of sugar ÷ quantity of sugar in a sack

                           = 28750 ÷ 500

                           =  57 sacks

6 0
3 years ago
Read 2 more answers
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