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3 years ago

Kaylee decided to donate 30% of her savings if she has $238 in her savings account about how much will she Donate

Mathematics

1 answer:

balu736 [363]3 years ago

3 0

Answer: Donate $71.40

Step-by-step explanation:

To calculate a percentage of an amount, we have to multiply that percentage by the amount and divide by 100.

Donate = $238 · 30 ÷ 100 = $7,140 ÷ 100 = $71.40

Answer : Donate $71.40

$\textit{\textbf{Spymore}}$

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Bobby bought two shares of stock, which he sold for $96 each. If he had a profit of 20 percent on the sale of one of the shares

pashok25 [27]

Answer:

The correct option is c) a loss of $8.

Step-by-step explanation:

Consider the provided information.

If the selling price of two item is same and one item sold at a profit of x % and other at a loss of x % in that case total sale result loss:

To calculate the loss use the formula: $Loss\ \%=(\frac{x}{10})^2\ \%$

It is given that he had a profit of 20 percent on the sale of one of the shares but a loss of 20 percent on the sale of the other share, where the selling price is $96 each.

That means the total sale result will be a loss.

Now use the above formula by substitute x=20.

$Loss\ \%=(\frac{20}{10})^2\ \%\\\\Loss\ \%=4\ \%$

It is given that the sales price is $96 of each that means total sales price is:

$96+$96=$192

Let the cost price of the shares were x.

According to question: x-4% of x = 192

$x-\frac{4}{100}\times x = 192\\\\x-0.04x = 192\\\\0.96x = 192\\x = 200$

Hence, the cost price of the shares was 200.

Loss = Cost price -Sales price

Loss = $200 - $192

Loss = $8

Hence, the correct option is c) a loss of $8.

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3 years ago

About % of the area under the curve of the standard normal distribution is between z = − 0.9 z = - 0.9 and z = 0.9 z = 0.9 (or w

prisoha [69]

Using the normal distribution, it is found that 63.18% of the area under the curve of the standard normal distribution is between z = − 0.9 z = - 0.9.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The area within 0.9 standard deviations of the mean is the <u>p-value of Z = 0.9(0.8159) subtracted by the p-value of Z = -0.9(0.1841)</u>, hence:

0.8159 - 0.1841 = 0.6318 = 63.18%.

More can be learned about the normal distribution at brainly.com/question/4079902

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Answer:

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-6 < -2 or -2 > -6

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