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NeTakaya
3 years ago
9

Im not sure what to do

Mathematics
1 answer:
motikmotik3 years ago
7 0

Answer:

h(-1)=\frac{-2}{3}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<u />h(x)=\frac{2x-6}{4x^2+8}<u />

h(-1) is x = -1

<u>Step 2: Evaluate</u>

  1. Substitute:                    h(-1)=\frac{2(-1)-6}{4(-1)^2+8}
  2. Exponents:                   h(-1)=\frac{2(-1)-6}{4(1)+8}
  3. Multiply:                        h(-1)=\frac{-2-6}{4+8}
  4. Subtract:                       h(-1)=\frac{-8}{4+8}
  5. Add:                              h(-1)=\frac{-8}{12}
  6. Simplify:                        h(-1)=\frac{-2}{3}
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