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Nesterboy [21]
3 years ago
12

Suppose h(t) = -7t² - 6t-18 models the height (in feet) of a person jumping off a cliff into a river while on vacation, as a fun

ction of time, t, in seconds. How high above the water is the cliff?
A. 7 feet
B. 6 feet
C. 18 feet
D. 29 feet​
Mathematics
1 answer:
quester [9]3 years ago
5 0
C. 18 ft is I think the answer
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The y intercept of the graph of the exponential decay equation
Sati [7]

decay - red

growth - blue

Answer: (0, 6)


6 0
3 years ago
Solve the equation on the interval 0 less than or equals theta less than 2 pi 0≤θ<2π. 2 cosine theta plus 1 equals 0 2cosθ+1=
VARVARA [1.3K]

Answer:

θ = 2π/3 or 5π/3

Step-by-step explanation:

2 cosθ + 1= 0

when  + 1 goes to R H S Side than it becomes negative by transposition   method

2 cos = -1

now by dividing by 2 both sides we get

cosθ  =  -\frac{1}{2}

since cosθ is negative

Cosθ = - cos 60°

it means either cosθ lies in 2nd or third quadrant

θ = π - π/3

or

θ = 2π- π/3

so θ = 2π/3 or 5π/3

6 0
3 years ago
Just number 14 please
larisa [96]
Nope you posted this five days ago no need for another answer.
4 0
3 years ago
The diagonal of rectangle ABCD measures 2 inches in
ryzh [129]

Answer:

B. √3

Step-by-step explanation:

Edge 2021

7 0
3 years ago
The manufacturer of hardness testing equipment uses​ steel-ball indenters to penetrate metal that is being tested.​ However, the
kumpel [21]

Answer:

Check the explanation

Step-by-step explanation:

Let X denotes steel ball and Y denotes diamond

\bar{x_1} = 1/9( 50+57+......+51+53)

=530/9

=58.89

\bar{x_2}= 1/9( 52+ 56+....+ 51+ 56)

=543/9

=60.33

difference = d =(60.33- 58.89)

=1.44

s^2=1/n\sum xi^2 - n/(n-1)\bar{x}^2

s12 = 1/9( 502+572+......+512+532) -9/8 (58.89)2

=31686/8 - 9/8( 3468.03)

=3960.75 - 3901.53

=59.22

s1 = 7.69

s22 = 1/9( 522+ 562+....+ 512+ 562) -9/8 (60.33)2

=33295/8 - 9/8 (3640.11)

=4161.875 - 4095.12

=66.75

s2 =8.17

sample standard deviation for difference is

s=\sqrt{[(n1-1)s_1^2+ (n2-1)s_2^2]/(n1+n2-2)}

 = \sqrt{[(9-1)*59.22+ (9-1)*66.75]/(9+9-2)}

= \sqrt{1007.76/16}

=7.93

sd = s*\sqrt{(1/n1)+(1/n2)}

=7.93*\sqrt{(1/9)+(1/9)}

=7.93* 0.47

=3.74

For 95% confidence level Z (\alpha /2) =1.96

confidence interval is

d\pm Z(\alpha /2)*s_d

=(1.44 - 1.96* 3.75 , 1.44+1.96* 3.75)

=(1.44 - 7.35 , 1.44 + 7.35)

=(-2.31, 8.79)

There is sufficient evidence to conclude that the two indenters produce different hardness readings.

3 0
3 years ago
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