Answer:
x<_2
Step-by-step explanation:
first off solve this like a regular equation the >_ dosent matter till later
so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)
so its 5x-13+x>_9x-7
add 5x and x to get 6x-13 on one side
then you get 6x-13>_9x-7 then subtract -9x from both sides
so its now -3x-13>_-7 add 13 so you get -3x>_6
then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2
that your final answer hope this helps :)
Answer:
D
Step-by-step explanation:
let y = f(x), that is
y = 
Rearrange making x the subject
Multiply both sides by 5
5y = 2x - 3 ( add 3 to both sides )
5y + 3 = 2x (divide both sides by 2 ) , then
x = 
Change y back into term of x, hence
(x) = 
→ D
Answer:
x = ±i(√6 / 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Algebra II</u>
Imaginary root i
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2x² + 3 = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
- [Division Property of Equality] Divide 2 on both sides: x² = -3/2
- [Equality Property] Square root both sides: x = ±√(-3/2)
- Simplify: x = ±i(√6 / 2)
