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earnstyle [38]
3 years ago
11

Find the area of the figure to the nearest thousandth.

Mathematics
1 answer:
puteri [66]3 years ago
6 0

Answer:

add 15+15+4 and you will have the total ft

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What is the number written in standard form :six million , seven hundred thousand,twenty
Luda [366]
It would be 670.002*10^4

4 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
Which one is it? need help please
klio [65]
When x = - 4 then
y = 1/2(-4) -6
y = -2 - 6
y = -8
solution (-4, -8)
answer is 
B. (-4, -8) second choice
3 0
3 years ago
Please help I really need help please ans thank you ​
Vinil7 [7]

Answer:

see below

Step-by-step explanation:

x = 63 and y = 27

180 - 117 Gives 63

3 0
3 years ago
Read 2 more answers
A curious patterns occurs in a group of people who all shake hands with one another. It turns out that you can predict the numbe
ycow [4]

Missing part of the question

Determine the number of handshakes, i, that will occur for each number of people, n, in a particular room. (people)

Answer:

S_n = \frac{n}{2}(n - 1)

Step-by-step explanation:

Given

For 5 people

\begin{array}{cc}{People} & {Handshakes} & {5} & {4} & {4} & {3} & {3} & {2} & {2} & {1} & {1} & {0} &{Total} & {10} \ \end{array}

Using the given instance of 5 people, the number of handshakes can be represented as:

(n - 1) + (n - 2) + (n - 3) + ........ + 3 + 2 + 1 + 0

The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.

S_n = \frac{n}{2}{(T_1 + T_n})

Where

T_1 = n - 1 --- The first term

T_n = 0 --- The last term

So:

S_n = \frac{n}{2}(n - 1 + 0)

S_n = \frac{n}{2}(n - 1)

7 0
2 years ago
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