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tekilochka [14]
2 years ago
6

shenika is inviting 7 friends to a party. if each friend will get 5 cookies and each box has 12 cookies. how many boxes does she

nika need to get
Mathematics
1 answer:
Naddik [55]2 years ago
8 0

Answer:

Shenika invites 7 friends and each one gets 5 cookies.

= 7*5

= 35

Based on above answer, Shenika will need a total of 35 cookies for all.

-----------------------------------------------------------------------------------------------------------

Each box has 12 cookies.

Total cookies = 35

Let the number of boxes be x.

12*x = 35

x = 35/12

x = 2.9

This means she would need <em><u>3 boxes</u></em>.

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A fruit stand has to decide what to charge for their produce. They need $5.30 for 1 apple and 1 orange. They also need $7.30 for
Aneli [31]

Answer:

A fruit stand has to decide what to charge for their produce.

They need $ 5.30 for 1 apple and 1 orange.

They also need $ 7.30 for 1 apple and 2 oranges.

TO DETERMINE

To put this information into a system of linear equations.

TO find a unique price for an apple and an orange

EVALUATION

Let the price of an apple = x and price of an orange = y

So From the first condition that they need $ 5.30 for 1 apple and 1 orange we get

\sf{x + y = 5.30}x+y=5.30 - - - - Equation 1

Again from second condition that they need $ 7.30 for 1 apple and 2 oranges we get

\sf{x + 2y = 7.30}x+2y=7.30 - - - - Equation 2

So the required Set of linear equations are

x + y = 5.30

x + 2y = 7.30

Equation (2) - Equation (1) we get

y = 2

From Equation (1) we get

x = 5.30 - 2 = 3.30

Hence price of an apple = $ 3.30

The price of an orange = $ 2

7 0
2 years ago
Read 2 more answers
How many blueberries on the on cake roof
sasho [114]

Answer:

say what

Step-by-step explanation:

6 0
3 years ago
The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

5 0
2 years ago
Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx

Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2\sqrt{x}+\int 1dx

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

9\text{ln}|x|+2\sqrt{x}+x+C

Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

4 0
2 years ago
What is the product of the two integer values for $x$ for which $|x^2 - 16|$ is a prime number?
Nana76 [90]

Answer:

-9

Step-by-step explanation:

x² -16 = (x -4)(x +4)

This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).

... For x-4 = ±1, x = 3 or 5

... For x+4 = ±1, x = -3 or -5

The values of x that are ±3 both give |x²-16| = 7, a prime.

The values of x that are ±5 both give |x²-16| = 9, not a prime.

The two values of x that are of interest are x=-3 and x=3. Their product is ...

... (-3)·(3) = -9

8 0
3 years ago
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