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3 years ago

Determine if the expression 9y5 – 10y3 is a polynomial or not. If it is a polynomial,

Mathematics

1 answer:

Stolb23 [73]3 years ago

8 0

I am going to assume that the equation was supposed to be $9y^{5}$ $-10y^{3}$

Answer:

It is a polynomial. It is a binomial and it has a degree of 5.

Step-by-step explanation:

A polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables so $9y^{5}$ $-10y^{3}$ will be considered a polynomial.

A binomial is a polynomial with 2 terms.

The degree of a polynomial is the highest exponent in it which in this equation is 5.

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Answer:

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Step-by-step explanation:

(h-k)(3)

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(x2+1-x+2)(3)

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3x2-3x+9

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3 years ago

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Answer:

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Step-by-step explanation:

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Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t

slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

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3 years ago

How do you work out 5 2/3 - 2 3/4 ???

loris [4]

Hi,
i worked out the problem and I attached the picture

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3 years ago

Explain how your know that 88is a solution to the equation 1/8 R = 11 complete the sentences

Eddi Din [679]

Answer:

In this equation R would equal 88 because it satisfies the equation.

Step-by-step explanation:

You must solve for R by isolating the variable(which is R). To move the 1/8, multiply both sides by 8. You would do this because 8 is the reciprocal of 1/8. With R on it's own, to keep both sides equal multiply 11*8. That equals 88, which satisfies the equation, which is why 88 is the solution.

Hope this helps :)

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3 years ago