If h= 13 units and r= 4 units, then what is the approximate volume of the cone shown above?

Mathematics

1 answer:

Rufina [12.5K]2 years ago

6 0

Answer:

≅217.82

Step-by-step explanation:

The volume of a cone of radius 4 is one third the area of the base B multiplied by the height (13).

therefore;

V = 1/3πr²h

Substituting the values in the equation gives;

V = 1/3π(4)²(13)

V ≅ 217.82 cubic units

You might be interested in

In the figure, lines a and b are parallel.

navik [9.2K]

Answer:

Step-by-step explanation:

Look at the picture.

Vertical angles, corresponding angles, alternate exterior angles are congruent.

Supplementary angles add up to 180°.

5 0

3 years ago

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

3 years ago

ASAP! BRAINLIEST!

nasty-shy [4]

Answer:

The average rate of change from 3 to 6 storms = 0.04

Step-by-step explanation:

Let number of Storms = N

And Predicted Gas Price = P

it is required to find the average rate of change from 3 to 6 storms.

At N = 3 ⇒ P = $2.44

At N = 6 ⇒ P = $2.56