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2 years ago

If h= 13 units and r= 4 units, then what is the approximate volume of the cone shown above?

Mathematics

1 answer:

Rufina [12.5K]2 years ago

6 0

Answer:

≅217.82

Step-by-step explanation:

The volume of a cone of radius 4 is one third the area of the base B multiplied by the height (13).

therefore;

V = 1/3πr²h

Substituting the values in the equation gives;

V = 1/3π(4)²(13)

V ≅ 217.82 cubic units

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Helene is finding the sum (9 10i) (–8 11i). She rewrites the sum as (–8 11)i (9 10)i. Which statement explains the property of a

Andreyy89

She made the mistake of grouping unlike terms and factorizing.

Given that

Helene is finding the sum (9 + 10i) + (–8 + 11i).

She rewrites the sum as (–8 + 11)i + (9 + 10)i.

We have to determine

Which statement explains the property of addition that she made an error in using?

According to the question

The mistake she did is in the second term distributing.

(9+10i) is not equal to (9+10)i

Similarly (-8+11i) is not equal to (-8+11)i.

The correct method she should have done is given below;

Grouping real terms together and imaginary terms together and finding the sum is,

$\rm = (9 + 10i) + (-8 + 11i)\\\\= 9+10i-8+11i\\\\= (9-8) +(10i+11i)\\\\=1+21i$

Hence, she made the mistake of grouping unlike terms and factorizing.

To know more about Complex Number click the link given below.

brainly.com/question/10078818

6 0

2 years ago

beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation i

skad [1K]

The given details are illustrations of addition and subtractions of fractions. The scuba driver is at an elevation of $-5\frac{1}{15}$ ft below the sea level.

Given that:

$n_1 = 1\frac 23$ --- the first dive

$n_2 = 3\frac 25$ ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

$d = 0 - n_1 - n_2$ --- we use subtraction because the diver is below the sea level

So, we have:

$d = 0 - 1\frac 23 - 3\frac 25$

$d = - 1\frac 23 - 3\frac 25$

Convert fractions

$d = - \frac 53 - \frac{17}5$

Take LCM

$d = \frac{-5 \times 5 - 17 \times 3}{15}$

$d = \frac{-76}{15}$

Reduce fraction

$d = -5\frac{1}{15}$

The above value means that the diver's elevation is at $-5\frac{1}{15}$ ft below the sea level.