Ok so we are gonna find the area or the rectangles on the object
Area of rectangle 1 = length x width
= 6 x 20
= 120 m square
Multiply the area of rectangle 1 by 2 because there are two same shaped rectangle.
120 x 2
=240 m square
Area of rectangle 2 = 30 x 6
= 180 m square
Multiply the area of rectangle 2 by 2 because there are two same shaped rectangle.
180 x 2
=360 m square
Area of rectangle 3 = 30 x 20
= 600 m square
Multiply the area of rectangle 3 by 2 because there are two same shaped rectangle.
600 x 2
=1200 m square
Then add all the area of the rectangles.
240 + 360 + 1200
= 1800 m square
Therefore the surface area is 1800 m square
Answer:
We know that:
If T = area of the triangle
and R = area of the rectangle:
I T - RI < 4.
Now, we know that:
T = 8*6/2 = 8*3 = 24
R = 4*(x - 4) = 4*x - 16
Then replacing those values, we can write:
I24 - (4*x - 16)I < 4
I40 - 4*xI < 4
Now let's solve it:
First we aim for the first value that is not a solutions, this is when:
I40 - 4*xI = 4
we can write this as:
40 - 4*x = +-4
The first extreme is:
40 - 4*x = +4
x = (40 - 4)/4 = 9
The other extreme is:
40 - 4*x = -4
x = (40 + 4)/4 = 11.
Then the set of solutions is: S = (9, 11)
Answer:
Volume required = 100mL
Step-by-step explanation:
Let the volume of 30% solution required be = V mL
Amount of solute in V mL of solution = 30% of V = 0.3V...............(i)
This amount is also present in 150 mL of 20% solution
For 150 mL of 20% solution we have amount of solute = 150 mL X 20%
= 30..............(ii)
Thus equating i and ii we get
0.3V = 30
Thus V =100 mL
The rule for the product of similar bases with exponents:
(a^b)(a^c)=a^(b+c)
(-5*6)(a^1)(a^8)
(-30)(a^(1+8))
-30a^9
Answer: 4 Notebooks
Step-by-step explanation:
The number of notebooks is x, the number of markers is 2x+3.
Since the price per notebook is $5 we can write it as 5x, And the price per marker is $2, we can write that as 4x+6
5x+4x+6=42
9x=36
x=4
so he bought 4 notebooks and 11 markers.
CHECK: 4*5=20 and 11*2=22 20+22=42
