Answer:
p=mv
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given
--- volume


Required
The surface area as a function of base length
The volume (V) is calculated as:



Make y the subject

Substitute 3 for V

The surface area of the open box is:


Substitute: 



Hence, the function is:

If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
<h3>What is a quadratic equation?</h3>
It's a polynomial with a worth of nothing.
There exist polynomials of variable power 2, 1, and 0 terms.
A quadratic condition is a condition with one explanation where the degree of the equation is 2.
Domain and range of linear and quadratic functions
Let the linear equation be y = mx + c.
Then the domain and the range of the linear function are always real.
Let the quadratic equation will be in vertex form.
y = a(x - h)² + k
Then the domain of the quadratic function will be real.
If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
More about the quadratic equation link is given below.
brainly.com/question/2263981
#SPJ4
Ok, so if you do the math.. 8³ •8^-5 =512.0000305
So, in conclusion... the student is correct..
Answer:11 hours
Step-by-step explanation: