1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
satela [25.4K]
3 years ago
6

11 is less than a number is more greater than 17 

Mathematics
1 answer:
laila [671]3 years ago
8 0

Answer:

This doesnt make, so re write the problem

Step-by-step explanation:

You might be interested in
Stephen uses
34kurt

Answer:

13.75 servings or 13 ¾ servings

Step-by-step explanation:

This is the correct question

Stephen uses 2/25 kilograms of tofu in each serving of his famous tofu dish. He has 1 1/10 kilograms of tofu.

To get answer  

We will have to divide the number of tofu required with the number of tofu own.  

Stephen uses 2/25 kilograms of tofu in each serving and he has 11/10 kilograms tofu.  

= (11/10) ÷ (2/25)  

= (11/10) ÷ (2/25)

   11/10 * 25/2 =

   275 ÷ 20= 13.75 servings or 13 ¾ servings

Stephen can make 13 ¾ or 13.75 servings

3 0
3 years ago
Read 2 more answers
Which table represents an exponential function?
slavikrds [6]

Answer:

Step-by-step explanation:

The second one.

8 0
3 years ago
Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are
Svetlanka [38]

Answer:

(a) Number of sets B given that

  • A⊆B⊆C: 2¹⁰.  (That is: A is a subset of B, B is a subset of C. B might be equal to C)
  • A⊂B⊂C: 2¹⁰ - 2.  (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

<h3>(a)</h3>

Let x_1, x_2, \cdots, x_{20} denote the 20 elements of set X.

Let x_1, x_2, \cdots, x_{10} denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain x_1, x_2, \cdots, x_{10}.

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from x_1, x_2, \cdots, x_{20}.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves 2^{10} -2 = 1024 - 2 = 1022 possibilities.

<h3>(b)</h3>

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's 2^{20} = 1048576 possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only 2^{20} - 2^{10} possibilities left.

5 0
3 years ago
If 5^2x=26, what is the value of x?<br><br> x≈4.05<br> x≈1.41<br> x≈1.01<br> x≈0.99
babunello [35]
The correct answer is x≈1.01
You're welcome. ;)
7 0
3 years ago
I need question a and b done pls help
FrozenT [24]

Answer:

A. 5

B. 12

Step-by-step explanation:

What you do is you substitute -2 into the a and the 3 into the b.

a. 3(-2)^2-5(3)+8                       b. 2/3(3)-5(-2)

3(4)-15+8                                   2-(-10)

12-15+8                                      12 is your answer.

-3+8

5 is your answer.

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the value of x the in the figure below? In this diagram, ABD~CAD
    12·1 answer
  • There are 4 red balls, 6 white balls, and 3 green balls in a bag. If one ball is drawn from the bag at random, what is the proba
    5·1 answer
  • Round 7.365 to the ones place.​
    8·1 answer
  • marlon has 3/4 pound of sliced. cheese he uses 1/8 pound of cheese on each sandwich he makes how many sandwiches can marlon make
    5·2 answers
  • Silicone implant augmentation rhinoplasty is used to correct congenital nose deformities. The success of the procedure depends o
    7·1 answer
  • Someone pls help me with this!!
    8·1 answer
  • What is the slope and y-intercept of the graph?<br> (2.1)<br> (-1.4)
    5·2 answers
  • A class’s test scores are normally distributed if the average score 60 and the standard deviation is 7 choose the spots where th
    15·2 answers
  • Hi my question is what is ma name?​
    6·2 answers
  • The sum of two polynomials is 8d5 – 3c3d2 5c2d3 – 4cd4 9. if one addend is 2d5 – c3d2 8cd4 1, what is the other addend? 6d5 – 2c
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!