Answer:
Step-by-step explanation:
Number of students 10
Problem 1. $625 for the bus hire per friday, So 625*4=$2500
Problem 2. 2500/25=$100 each for the whole 4 weeks
Problem 3.
10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each
20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each
30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each
41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each
Hope this is correct
The given above is are triangles, as per the proof the line segments on top and bottom part are parallel. Also, it is given that two pairs of the angles of the triangles are congruent.
The triangles also share one common side, CA. Since, this side is between the angles the postulate that will prove the congruence of the triangles is ASA.
The answer to this item is the third choice.
Dear Kellyeasterday, 11 1/4 inches is more precise.
Answer: d. 512
Step-by-step explanation:
You need to remember that:
![(\sqrt[3]{x})^3=x](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%7D%29%5E3%3Dx)
Then, given the equation:
![\sqrt[3]{n}=8](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3D8)
You can find the value of "n" that make the equation true, by solving for "n".
So, to solve for "n", you need to raise both side of the equation to power 3. Therefore, you get:
![\sqrt[3]{n}=8](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3D8)
![(\sqrt[3]{n})^3=(8)^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bn%7D%29%5E3%3D%288%29%5E3)

Then, the value of "n" that makes the equation
true is: 512 (You can observe that this matches with the option d).