There's seven-eighths of a gallon of chocolate ice cream in the freezer. There's also two-thirds of a gallon of vanilla ice crea
1 answer:
There's seven-eighths of a gallon of chocolate ice cream in the freezer. There's also two-thirds of a gallon of vanilla ice cream.
gallons of chocolate ice-cream
gallons of vanilla ice-cream
To find how much more chocolate ice cream is there than vanilla
We subtract vanilla from chocolate
To subtract fractions we make the denominators same
least common denominator is 24
of a gallon
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To solve this we are going to use the exponential function: 
where
is the final amount after 
years
is the initial amount
is the decay or grow rate rate in decimal form
is the time in years
Expression A
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate, we are going to use the formula: 
*100%
*100%
*100%
5%
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at
We can conclude that the initial value of expression A is 624.
Expression B
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
*100%
*100
*100%
*100%
12%
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at
The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.
where
Expression A
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at
We can conclude that the initial value of expression A is 624.
Expression B
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at
The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.