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vitfil [10]
3 years ago
8

Help me on question 3 pls I’m giving out brainlest

Physics
1 answer:
emmasim [6.3K]3 years ago
3 0

Answer:

Its 150?

Explanation:

5³= 5×5×5

I hope its help :)

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Express 79 m in units of (a) centimeters
dem82 [27]

Answer: a) 7,00 centimeters

(b) 259. 19 feet

(c) 3110.28 inches

(d) 0.049 miles

Explanation:

(a) We know that 1 meter = 100 centimeters

Therefore,

79\ m= 7,900\text{ centimeters}

(b)Since 1 meter = 3.28084 feet

Then, 79\ m= 79\times3.28084=259.18636\approx 259.19\text{ feet}

(c) Since, 1 feet = 12 inches.

79\ m=259.19\text{ feet}=259.19\times12=3110.28\text{ inches}

(d) \text{Since 1 feet= }\dfrac{1}{5280}\text{ mile}

79\ m=259.19\text{ feet}=\dfrac{259.19}{5280}= 0.0490890151515\approx0.049\text{ miles}

8 0
4 years ago
The __________ of exercise determines the health and fitness benefit of the exercise. A. frequency B. intensity C. time D. type
MariettaO [177]

Answer:

c- Time

Explanation:

The time will tell depending on the person who is exercising, the rate of time, the  workout time. & limits on weights....

6 0
3 years ago
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What is table salt (NaCl) formed by?
Rzqust [24]
NaCl is a compound formed by a chemical reaction between Na (Sodium) and Cl (Chlorine). Sodium is an alkai metal in Group One of the Periodic Table, and it is very reactive. All alkai metals react violently with water and they are often found combined in nature because they are that reactive. Chlorine is a halogen in Group 17 of the Periodic Table and they are very reactive. 
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3 years ago
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A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to
irinina [24]

When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

<h3>Frictional force between the block and the horizontal surface</h3>

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Learn more about frictional force here: brainly.com/question/4618599

8 0
2 years ago
A 20-kg barrel is rolled up a 20-m ramp to the back of a truck whose floor is 5.0 m above the ground. What work is done in loadi
oee [108]

The angle of inclination is calculated using sin function,

sin θ = 5 m / 20 m = 0.25

θ = 14.4775° 

 

<span>The net force exerted is then calculated:
F net = m g sin θ = 20 * 9.8 * 0.25 </span>

F net = 49N 

<span>Work is product of net force and distance:
W = F net * d = 49 * 20 </span>

<span>Work = 980 J </span>

4 0
3 years ago
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