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mr Goodwill [35]
3 years ago
5

In order to keep a vehicle in a turn without allowing centrifugal force to pull the car out, what should you not do?

Physics
1 answer:
ELEN [110]3 years ago
6 0

Answer:D

Explanation:

In order to keep a vehicle in a turn without allowing centrifugal force to pull the car out one must accelerate while taking a turn.

Accelerating while turning allows vehicle to escape out effect of centrifugal force and maintain the traction with the road and prevent slipping.

Also whenever a car is turning it is accelerating because the direction of velocity vector is constantly changing which creates centripetal acceleration on car.                          

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An object has a mass of 785 g and a volume of 15 cm³. What is its density? (Give your answer in g/cm³ to 2 decimal places).
Anvisha [2.4K]

Answer:

denisity = 52.33 g/cm^{3}

Explanation:

Density:

d = \frac{m}{v}

We have that m = 785 and that v = 15 cm^{3}.

d = \frac{785}{15}

d = 52.33 m^{3}

4 0
3 years ago
Why do planets not travel in a straight path?
Elis [28]

Answer:

Because the gravitational attraction of the Sun hold them in motion around it

Explanation:

For an object travelling in a straight path at constant velocity, the net force acting on the object must be zero.

The planets in the Solar System, however, do not experience a zero net force: in fact, the Sun exerts a gravitational attraction on them, whose magnitude is given by

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M is the mass of the Sun

m is the mass of the planet

r is the average distance between the Sun and the planet

Due to the presence of this force, the Sun makes the planets 'deviating' from their straight path, forcing them to following an elliptical path around the Sun.

6 0
4 years ago
The index of refraction for red light in a certain liquid is 1.303; the index of refraction for violet light in the same liquid
kotegsom [21]
Snell's law states: n1/n2 = Sin Ф2/Sin Ф1

But n2/n1 = 1.303 and 1.326 for red light and violet light respectively (for this case) and Ф1 = 45

Therefore,
Фr = Sin ^-1{1/1.303 *Sin 45} = 32.87°
Фv = Sin ^-1 {1/1.326* Sin 45} = 32.23°

Then,
Dispersion, Фv - Фr = 32.23 - 32.87 = -0.64°
3 0
4 years ago
A 0.0750kg teddy bear is dropped from a deck that is 3.00m above the ground. What will be the velocity of the teddy bear as it s
FrozenT [24]

The velocity of the teddy bear as it strikes the ground is 7.67 m/s.

<h3>Velocity of the teddy when it strikes the ground</h3>

The velocity of the teddy when it strikes the ground is calculated from principle of conservation of energy as shown below.

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • h is height of fall of the teddy
  • g is acceleration due to gravity

v = √(2 x 9.8 x 3)

v = 7.67 m/s

Thus, the velocity of the teddy bear as it strikes the ground is 7.67 m/s.

Learn more about conservation of energy here: brainly.com/question/166559

#SPJ1

4 0
2 years ago
A truck covers 40.0 m in 7.45 s while uniformly slowing down to a final velocity of 2.35 m/s.
Mamont248 [21]
It would be around 6.24 sec
7 0
4 years ago
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