All categories

3 years ago

A car travels 30 km north in 25 min. And 40 km east in 35 min. What is the total distance traveled

Physics

1 answer:

Stella [2.4K]3 years ago

4 0

Answer:

70 km

Explanation:

Before answering, let's remind the difference between distance and displacement:

- Distance: the total length of the path covered, no matter in which direction

- Displacement: the distance in a straigth line between the final point and the starting point of the motion

In this problem, we are asked to find the total distance travelled. So, we can simply add the length of the two parts of the path, regardless of their direction:

d = 30 km + 40 km = 70 km

You might be interested in

While running around the track at school, Milt notices that he runs due East in the 100m homestretch and due West on the 100m ba

Sergeeva-Olga [200]

They have equal magnitudes and opposite directions.

5 0

3 years ago

Read 2 more answers

1. Meiosis produces daughter cells that are

Marina86 [1]

Answer:

1. A Haploid

2. A. Somatic Cell production

3. B. Gametic cell production

4. C. Mitosis produces identical cells to parent cells.

5. B 4:0

6. C Both parent bees are heterozygous Ll

7. D DNA is made up of chromosomes

8. B Each hypothesis was tested and DNA supported the data better

9. D There may be an increase in pest populations that are resistant to control measures.

10. A They are proven to cause cancer.

11. B a form of a gene

Explanation:

Answer was too long, so is attached in a word document

Download docx

5 0

3 years ago

A shell is shot with an initial velocity v with arrow0 of 18 m/s, at an angle of θ0 = 60° with the horizontal. At the top of the

BARSIC [14]

Answer:

D = 43 m

Explanation:

given,

initial velocity = 18 m/s

angle θ = 60°

total horizontal distance covered by the shell is

$R = \dfrac{v_0^2sin 2\theta}{g}$

applying conservation of momentum in horizontal direction

m v₀ cos θ = m₁v₁ + m₂ v₂

m v₀ cos θ = 0.5 m v₂

v₂ = 2 v₀ cos θ.

distance covered by the shell from point of explosion

R' = v t

= $(2 v_0 cos \theta) (\dfrac{v_0^2sin \theta}{g})$

= $(2 \dfrac{v_0^2cos \theta sin \theta}{g})$

= $\dfrac{v_0^2sin 2\theta}{g}$

= R

total distance traveled by the shell is

D = $\dfrac{R}{2}+R'$

= 1.5 R

= $1.5\dfrac{v_0^2sin 2\theta}{g}$

D = $1.5\dfrac{18^2sin 2\times 60}{9.81}$

= 42.9 ≅ 43 m

D = 43 m

3 0

3 years ago

A fly wheel with a diameter of 1.20m is rotating at an angular speed of 200 Rev/min

gladu [14]

Answer:a) 20.944rad/s (b) 12.57m/s (c) 800rev/min²

Explanation:

5 0

3 years ago

A rod of length L is pivoted about its left end and has a force F applied perpendicular to the other end. The force F is now rem

timurjin [86]

Answer:

$F' = 4F$

Explanation:

When force applied to the end of the rod in perpendicular direction then net torque on the rod is given as

$\tau = L F sin90$

$\tau = LF$

Now another force is applied at mid point of the rod at an angle of 30 degree with the rod

so new value of torque is given as

$\tau = \frac{L}{2}F' sin\theta$

$LF = \frac{L}{2}F' sin30$

$LF = \frac{F'L}{4}$

so we have

$F' = 4F$

3 0

3 years ago