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3 years ago

Write an expression for the nth term of the geometric sequence. Then find the indicated term. a1 = 3, r = 3 , n = 10

Mathematics

1 answer:

MissTica3 years ago

6 0

Answer:

$A_{n} =3(3)^n^-^1$

$A_{10} = 59,049$

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If you help with the correct answer u are a god .pt2

Brrunno [24]

a. Answer: D: (∞, ∞)

R: (-∞, ∞)

Step-by-step explanation:

Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).

Theoretical range is the range of the equation given the domain.

c(p) = 25p

There are no restrictions on the p so the theoretical domain is All Real Numbers.

Multiplying 25 by All Real Numbers results in the range being All Real Numbers.

a) D: (∞, ∞)

R: (-∞, ∞)

*********************************************************************************

b. Answer: D: (0, 200)

R: (0, 5000)

Step-by-step explanation:

Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.

Practical range is the range of the equation given the practical values of the domain.

The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200

The range is 25p → (25)0 ≤ (25)p ≤ (25)200

→ 0 ≤ 25p ≤ 5000

b) D: (0, 200)

R: (0, 5000)

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Elena L [17]

Y= ∛(-x) - 3
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for x= 8 → y= ∛(-8) - 3 ↔ y = -2 -3 ↔ y = -5
Then - 5≤ y≤ - 1
hence the range of y is {y|-5≤y≤-1}

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Answer:

They should in crease budget.

Step-by-step explanation:

divide each number by 2 to see how often they go equally/use the data table you have available of the two climbers.

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Pretty certain it would be the first answer - X = 6 square root of 2
Y = 6

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poizon [28]

Answer:

$(\frac{a^{2}b^{-3} }{a^{-2}b^{2} })^{2} = (a^{2-(-2) }b^{-3 - 2})^{2} \\ = (a^{4}b^{-5} )^{2} = (a^{4})^{2} (b^{-5})^{2} = a^{8} b^{-10}$

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Step-by-step explanation:

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