Use inequality symbol to compare -3+7__-10-2?

Mathematics

2 answers:

Firdavs [7]2 years ago

5 0

-3 + 7 ___ -10 - 2
4 > -12

Radda [10]2 years ago

5 0

First we need to solve them

-3+7 = 4

-10-2 = -12

As a result -12 is less than 4

The inequality symbol to compare it is this : >

-3+7 > -10-2

I hope that's help and if you have any question please let me know.

You might be interested in

A hiker walks at a speed of 3 2/5 km per hour. how many km will he walk in 3/4 of an hour

Art [367]

Answer:

2.55

Step-by-step explanation:

6 0

3 years ago

48 students are girls they make up 60% of the class how many students total

qwelly [4]

For this you would do
$48 \div .60$
Because 60% is the same as 0.60. And solving a problem like this is the opposite of finding a percent of a number. When you solve this you get 80. So there are 80 students in total.

5 0

3 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

Solve for the variable: 12.9 = x + 7.1 5.8 -5.8 20 -20

olya-2409 [2.1K]

12.9 = x + 7.1
subtract 7.1 from both sides to isolate the variable, x.

5.8 = x

5.8 is your answer.

3 0

3 years ago

Help me with this math question

nasty-shy [4]

Answer:

$\huge \boxed{K=20}\checkmark$