B, it is located on the 2nd quadrant
Answer:
The dimension of the cardboard is 34 cm by 34 cm by 17 cm.
Step-by-step explanation:
Let the dimension of the cardboard box be x cm by y cm by z cm.
The surface area of the cardboard box without lid is
f(x,y,z)= xy+2xz+2yz.....(1)
Given that the volume of the cardboard is 19,652 cm³.
Therefore xyz =19,652
......(2)
putting the value of z in the equation (1)


The partial derivatives are


To find the dimension of the box set the partial derivatives
and
.Therefore 
.......(3)
and 
.......(4)
Now putting the x in equation (3)



⇒y=34 cm
Then
=34 cm.
Putting the value of x and y in the equation (2)

=17 cm.
The dimension of the cardboard is 34 cm by 34 cm by 17 cm.
If it is 0.03,0.12,0.12 just add 0.09.
The next two numbers are 0.30,0.39
Answer:
The two numbers are 52 and 12.
Step-by-step explanation:
x+y=64
x=16+3y
Now, substitute the second equation into the first one.
16+3y+y=64
16+4y=64
4y=48
y=12
Substitute 12 into one of the equations in order to find x.
x=16+3(12)
x=16+36
x=52
Answer:
It would have to be 650
Step-by-step explanation:
Hope this helped