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3 years ago

Systems of equations needs to be solved in substitution form I will give five stars for the answer

Mathematics

1 answer:

Greeley [361]3 years ago

6 0

Answer:

x=2

Step-by-step explanation:

Just copie the picture

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What is the volume of a rectangular prism with a length of 1. 4 meters, a width of 0. 5 meter, and a height of 1. 8 meters? 7. 5

mihalych1998 [28]

The volume of the rectangular prism will be $V=1.26m^{3}$

<h3>What will be the volume of the rectangular prism ?</h3>

Given that

$\rm Lenth \ of \ the \ rectangular \ prism =1.4\ m$

$\rm width\ of \ prism=0.5\ m$

$\rm Height \ of \ prism=1.8\ m$

$\rm Volume \ of \ the \ Rectangular \ Prism= L\times W\times H$

$V=1.4\times 0.5\times1.8=1.26 \ m^{3}$

Thus the volume of the rectangular prism will be $V=1.26m^{3}$

To know more about the volume of the rectangular prism follow

brainly.com/question/24284033

6 0

2 years ago

How to slove step by step

wariber [46]

$\frac{x+3}{12}$ = $\frac{2}{7}$

Multiply both sides by 12, so that we get rid of the fraction in x.

12 · (x+3)/12 = 2/7 · 12

Simplify.

x + 3 = 24/7

Then, subtract 3 from both sides, so that "x" gets isolated.

x = 24/7 - 3

Turn "3" into an improper fraction so that we could find the value of x easier.

3 = 21/3

So :

x = 24/7 - 21/7

Simplify.

x = 3/7

~Hope this helps!~

7 0

3 years ago

A picture is 46 cm by 32 cm. A scale diagram of the picture must fit in a space that is 3 m by 2 m. Which scale would be the mos

Marrrta [24]

Answer:

A picture that is 46cm by 32 cm must fit in a space that is 3m by 2m

First, let's rewrite both of these dimensions in the same units.

Knowing that:

1m = 100cm

Then the dimensions of the space can be rewritten from:

3m by 2m

to:

300cm by 200cm

So, if we enlarge our original picture by a scale factor K, the new dimensions of the picture will be:

K*46cm by K*32cm

Now we just need to find a value of K such that:

K*46cm is something near to 300cm

K*32cm is something near to 200cm

First, we can solve the equation:

K*46cm = 300cm

solving this for K we get:

K = 300cm/46cm = 6.5

While if we solve the equation:

K*32cm = 200cm

we get:

K = 200cm/32cm = 6.25

So we got two possible scale factors.

Which one we should take?

Notice that if we wanted to use the larger one (K = 6.5) for the 32cm side. the new length would be:

32cm*6.5 = 208cm

This is larger than the 200cm of space that we have

Then we can not select the larger option, we can only take the other value:

K = 6.25

Then we can conclude that a reasonable scale factor to use is K = 6.25

4 0

3 years ago

Determine the equation of the graph, and select the correct answer below.

VMariaS [17]

Answer:

oh ya i need that my jdjdkdkdkdd

6 0

2 years ago

Each journal weighs about 280 grams. What is total weight of 3 journals?

victus00 [196]

280*3= 840
3 journals is about 840 grams

8 0

3 years ago

Read 2 more answers