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3 years ago

What is the correct solution set for the following graph?

Mathematics

1 answer:

Serhud [2]3 years ago

8 0

Answer: i do not see a graph

Step-by-step explanation:

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2 years ago

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3 years ago

A line is drawn so that it passes through the points (-3, -1) and (4, 2).

marishachu [46]

Answer:

(A) $\boxed{\bold{y=\frac{3}{7}x+\frac{2}{7}}}$

(B) $\boxed{\bold{2 \ = \ \frac{3}{7} * \ 4 \ + \ \frac{2}{7} }}$

Explanation:

(A) Slope: y = mx + b

m = 3/7

b = 2/7

Slope = $\bold{\frac{y_2-y_1}{x_2-x_1}}$

$\bold{\left(x_1,\:y_1\right)=\left(-3,\:-1\right),\:\left(x_2,\:y_2\right)=\left(4,\:2\right)}$

M = $\bold{\frac{2-\left(-1\right)}{4-\left(-3\right)}: \ \frac{3}{7} }$

Y intercept

$\bold{y=\frac{3}{7}x+b}$

Plug in $\bold{\left(-3,\:-1\right)\mathrm{:\:}\quad \:x=-3,\:y=-1}$

$\bold{-1=\frac{3}{7}\left(-3\right)+b}$

Isolate B

$\bold{-1=\frac{3}{7}\left(-3\right)+b}$

b = $\bold{\frac{2}{7} }$

(B) 4 = x, 2 = y

2 = 3/7 * 4 + 2/7

5 0

3 years ago

Read 2 more answers

Problem

Sergeu [11.5K]

The lengths of HJ and JK are 50 and 72 respectively.

Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.

The line HJ and JK are collinear then the total length is given as: HJ+JK=HK

substitute values

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

Learn more about collinear lines here: brainly.com/question/27943430

#SPJ10

8 0

2 years ago

Read 2 more answers

Find the mirror image of the point (1,4) reflected on the line x=3

fiasKO [112]

hope it helps

plz.mark as brainliest

4 0

3 years ago