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djyliett [7]
3 years ago
12

What is the y-intercept of the line shown? (4 points) 3.5 0 1 3

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0

People shoot their shot and they try to call me out

But really wanna diss so they can have some of my CLOOOUT

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Help please ASAP!!!! I NEED CORRECT ANSWERS ONLY FOR BRAINLIEST
MrRissso [65]

Let us start subtracting 3 cos theta both sides so that we may get all theta terms on left side only

It is now : 4 cos theta - 3 cos theta = - (sqrt3)/ 2

1 cos theta = -( sqrt 3 ) /2

we know cos (pi-x)= - cos x And cos (pi+ x)= - cos (x)

********* let us first use :

- Cos ( pi - theta) = - ( sqrt 3 )/2

this implies cos (pi- theta )= (sqrt 3) /2

cos ( pi - theta )= cos (pi /6)

pi- theta = pi/6

pi- pi/6 = theta

5 pi/6 = theta

one of teh answer is 5 pi/6 . another value of theta would be :

(2pi - 5pi/6)= 7pi/6

Answer: 5 pi/6 and 7 pi/6

5 0
3 years ago
HELPPP!! BRAINLIEST IF U ANSWER
makvit [3.9K]

Answer:

180

Step-by-step explanation:

k = 3

v = 60

(Found v by dividing any of the top numbers by the bottom number, ex: 420/7 = 60)

3k = 3(60)

3k = 180

6 0
3 years ago
Read 2 more answers
Oliver climbed 222 meters of a steep mountain reach the summit. He then rappelled down the other side of the mountain to return
nikdorinn [45]
B -222

Because he fell/descended 222 meters. And falling or going down produces a negative integer. Also, if you were actually doing the math to try to find where Oliver is currently located, you wouldn't add 222, or 0, or subtract -444. You would subtract 222. 

In addition, be aware that the question is asking you an integer to represent a situation, not the answer of where Oliver is. 

6 0
3 years ago
A pizza parlor offers pizzas with diameters of 8 in, 10 in, and 12 in. find the area of each size pizza. round to the nearest te
MaRussiya [10]
Area od pizza, A = Pi*Diameter^2/4

A1 = Pi*8^2/4 = 50.27 in^2
A2 = Pi*10^2/4 = 78.54 in^2
A3 = Pi*12^2/4 = 113.10 in^2

Cost (C) per sq. in;
C1 = 50.27/9 = $5.59
C2 = 78.54/12 = $6.55
C3 = 113.10/18 = $6.28

The best buy is the first pizza with 8 in diameter as it costs the least per sq. inch.
3 0
3 years ago
Read 2 more answers
Please I really need help
ohaa [14]

9514 1404 393

Answer:

  • scale factor: 3
  • rule: (x, y) ⇒ (3x +15, 3y -24)
  • center: (-7.5, 12)

Step-by-step explanation:

The scale factor can be found by comparing the length of CB to the length of RQ.

  B-C = (-2, 8) -(-4, 9) = (2, -1)

  Q-R = (9, 0) -(3, 3) = (6, -3)

The length of RQ is clearly 3 times the length of CB, so the scale factor (k) is ...

  ratio of corresponding differences = 6/2 = -3/-1 = 3 . . . . . scale factor

__

We know that for dilation about a point O, the distance from O is multiplied by the scale factor. For dilation of point B to point Q, this means ...

  k(B -O) = (Q -O)

Solving for Q, we get ...

  Q = kB -kO +O . . . . this is what our dilation rule will look like.

The quantity O-kO can be found by subtracting kB:

  Q -kB = O -kO = O(1 -k)

This is what we need for our dilation rule.

  Q -kB = (9, 0) -3(-2, 8) = (9+6, 0-24) = (15, -24)

So, our dilation rule is ...

  (x, y) ⇒ k(x, y) +(15, -24)

  (x, y) ⇒ (3x +15, 3y -24) . . . . . dilation rule

__

The center of dilation can be found from ...

  (Q -kB)/(1 -k) = O

  O = (15, -24)/(1 -3) = (-7.5, 12)

The center of dilation is (-7.5, 12).

_____

<em>Additional comments</em>

On the graph, the center of dilation can be found by drawing a line through a point and its image. (Points are always dilated along a line through the center of dilation.) The intersection of two such lines is the center of dilation.

On this graph, the center is just above the top edge of the chart, at point (-7.5, 12). You can see this if you carefully draw lines BQ and AP.

You usually have coordinates for two original points and two image points, so finding the scale factor the way we did is not difficult. If you just have one point on the original and the image, the scale factor is found by finding their distances from the center of dilation. Each image point is k times as far as each original point from that center.

7 0
3 years ago
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