2 years ago

5x (x - 4) = 0 Solve it in standard form

Mathematics

1 answer:

murzikaleks [220]2 years ago

4 0

Answer:

x=0 or x=4

Step-by-step explanation:

5x(x−4)=0

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Expand. Your answer should be a polynomial in standard form. (3c + 2)(c^2-6c-4)

evablogger [386]

Answer:

After expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

Step-by-step explanation:

We need to expand the polynomial $(3c + 2)(c^2-6c-4)$

Multiply the terms:

$(3c + 2)(c^2-6c-4)\\=3c(c^2-6c-4)+2(c^2-6c-4)\\=3c^3-18c^2-12c+2c^2-12c-8\\=3c^3-18c^2+2c^2-12c-12c-8\\=3c^3-16c^2-24c-8$

So, after expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

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2 years ago

Find 15/4 + (-4 1/3). Write your answer as a fraction in simplest form.

Montano1993 [528]

Answer:

-17/12

Step-by-step explanation:

15/4 = 3 3/4

3 3/4 -4 1/3 = 3 9/12 -4 4/12 = -17/12

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2 years ago

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2 years ago

Radius and diameter

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Answer:

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3 years ago

The half-life of a certain radioactive material is 83 hours. An initial amount of the material has a mass of 67 kg. Write an exp

Anvisha [2.4K]

Answer:

Initial amount of the material is 67 kg
Hal-life is 83 hours

The required equation is:

m(x) = 67 * $(1/2)^{x/83}$ , where m- remaining amount of the radioactive material, x - number of hours

After 5 hours the material remains:

m(5) = 67 * $(1/2)^{5/83}$ = 64.260 (rounded)

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2 years ago