This question was not written properly
Complete Question
Find the minimum value of the function f(x) = 0.9x² + 3.42x - 2.4 to the nearest
hundredth.
Answer:
The minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
Step-by-step explanation:
Our quadratic equation =
ax² + bx + c
f(x) = 0.9x² + 3.42x - 2.4
The minimum value of x formula=
x = -b/2a
a = 0.9
b = 3.42
x = -3.42/2 × 0.9
x = -3.42/1.8
x = -1.9
We input the value x in order to get the minimum value of y
f(x) = y
f(x) = 0.9x² + 3.42x - 2.4
f(-1.9) = 0.9(-1.9)² + 3.42(-1.9) - 2.4
= 3.249 - 6.498 - 2.4
=3.249 - 8.898
= -5.649
Approximately to the nearest hundredth = -5.65
Therefore, the minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
2(x-10)exponent2 is the answer
In the given series, we see that the first term is 3 and
the common ratio between the succeeding terms is -3. To solve for the sum of
the first 8 terms, we use the equation,
Sum = (a1)(1 – r^n) / (1 – r)
Substituting the known terms,
Sum
= (3)(1 – (-3)^8)/(1 - -3) = -4920
<span>Thus, the answer is -4920.</span>
Using PADMAS really works
