Question

Given that f(x) = x2 – 3x – 28 and g(x) = x - 7, find

Answer 1

Answer:

$(f-g)(x)=x^2-4x-21$

Step-by-step explanation:

We are given the two functions:

$f(x)=x^2-3x-28\text{ and } g(x)=x-7$

And we want to find:

$(f-g)(x)$

This is equivalent to:

$=f(x)-g(x)$

Substitute:

$=(x^2-3x-28)-(x-7)$

Distribute:

$=x^2-3x-28-x+7$

Rearrange:

$=(x^2)+(-3x-x)+(-28+7)$

Hence:

$(f-g)(x)=x^2-4x-21$