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3 years ago

A cube with an edge of length s has a volume of 27 units. What is the length of s?

Mathematics

1 answer:

matrenka [14]3 years ago

5 0

Answer:

s = 3

Step-by-step explanation:

The volume formula for a cube is V = s^3, where “s” is the edge length. Since we know the volume and need to find “s,” we just do the inverse operation for an exponent, which is a radical. The cubed root of 27 is 3, so there’s your answer! Hope this is helpful & accurate. Best wishes.

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2x – 3y = 18<br> Solve for y.

Nataly [62]

Answer:

y= -6+2/3x

Step-by-step explanation:

2x-3y=18

Minus the 2x from both sides

-3y=18-2x

Then divide both sides by -1

-3y÷-1=18÷-1 -2x÷-1

Lastly divide both sides by 3

3y÷3= -18÷3+2x÷3

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3 years ago

Find the value of x. Round your answer to the nearest tenth. tan 12 degrees= ten over (x)

Lorico [155]

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3 years ago

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Simplify: - 4x 5x - 1 + 3-6x 3-6x

Vitek1552 [10]

Answer:

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Solution:

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Step-by-step explanation:

I hope that this is what you are looking for

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3 years ago

How could you model 5 students sharing 4 bags of popcorn equally? How much will each student get?

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3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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3 years ago

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