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3 years ago

PLSSSS HELPPP I WILLL GIVEEE BRAINLIESTTTT!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

lbvjy [14]3 years ago

7 0

Answer:

slope is 0

Step-by-step explanation:

I used another app to find the awnser for you

Trava [24]3 years ago

5 0

Answer:

slope is 0

Step-by-step explanation:

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Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠P

Anna [14]

The equation to be used to calculate the measure of ∠PQR in the cyclic quadrilateral is: (6x − 4)° + (2x + 16)° = 180°.

<h3>What are Opposite Angles in a Cyclic Quadrilateral?</h3>

A cylcic quadrilateral is a quadrilateral inscribed in a circle. The opposite angles are supplementary, that is they add up to give 180 degrees.

Thus, angles Q and O are opposite angles in the cyclic quadrilateral, which means they are supplementary.

Therefore, the equation to be used to calculate the measure of ∠PQR in the cyclic quadrilateral is: (6x − 4)° + (2x + 16)° = 180°.

Learn more about cyclic quadrilateral on:

brainly.com/question/10057464

8 0

3 years ago

Read 2 more answers

I’ll put you as brainliest

kari74 [83]

The law of an object moving with constant acceleration is

$s(t)=s_0+v_0t+\dfrac{1}{2}at^2$

Where $s$ is space, $t$ is time, $s_0$ is the initial position, $v_0$ is the initial velocity and $a$ is the acceleration.

In this case, if we choose a reference grid with the vertical axis pointing upwards, the acceleration of gravity will point downwards (and thus be negative). The initial position is zero, because the rocket is on the ground, and the initial velocity is 100 (positive because pointing upwards).

So, its law is

$h(t)=100t-\dfrac{1}{2}gt^2$

(I changed $s$ for $h$ since the rocket is moving vertically, so its position is actually its height. Also, g is the acceleration due to gravity).

The rocket hits the ground if its height is zero, so if we set $h=0$ we have

$0=100t-\dfrac{1}{2}gt^2 \iff t(100-\dfrac{1}{2}gt)=0$

Solving for t, we have either t=0, or

$100-\dfrac{1}{2}gt=0 \iff 100=\dfrac{1}{2}gt \iff 200=gt \iff t=\dfrac{200}{g}$

The solution t=0 means that at the beginning the rocket is on the ground. So, we're interested in the other solution. Considering that g is about 32.2 feet/s^2, we have

$t=\dfrac{200}{g}\approx \dfrac{200}{32.2}\approx 6.21$

3 0

3 years ago

Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is

Simora [160]

The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: $A=s^2$
Were
$A$ is the area in square kilometers
$s$ is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so $s=0.9$ . Lets replace that value in our formula to find $A$ :
$A=(0.9)^2$
$A=0.81$

Now, to find the population density of the filed, we are going to use the population density formula: $P_{d}= \frac{I}{A}$
where
$P_{d}$ is the population density in <span>in burrows per square kilometer
</span> $I$ is the number of burrows
$A$ is the are of the field
We know that $I=1980$ and $A=0.81$ , so lets replace those values in our formula:
$P_{d}= \frac{1980}{0.81}$
$P_{d}=2444.4$

We can conclude that the <span>density of prairie dog burrows is approximately 2444 burrws per square kilometer.</span>

5 0

3 years ago

What is the value of h

Marta_Voda [28]

I believe it would be 0 fr

8 0

3 years ago

Solve the following equation for a a-32=47

Verizon [17]

Answer:

value of a = 79

Step-by-step explanation:

by solving it we get,

=》a - 32 = 47

=》a = 47 + 32

=》a = 79

hence, a = 79

6 0

3 years ago

Read 2 more answers