I NEED HELP ON THIS PROBLEM QUICKLY PLEASE AND THANK YOU

A train leaves the station at time = 0. Traveling at a constant speed, the train travels 330 kilometers in 3 hours. Answers part

amid [387]

Answer:

The function that relates the distance traveled d to the time t is

f(t) = 110t, where d = f(t)

Step-by-step explanation:

From the question, we were told that the train is At a constant speed, the train travels 330 kilometers in 3 hours

We were told to write function that relates the distance traveled d to the time t, we can do this by writing a linear equation with those functions

Since we are told that the train travels 330 kilometers in 3 hours, then we can say the train travel (330/3) kilometers in 1 hour which means it travel 110 kilometers in 1 hour

Then d= 110t---------------eqn(1)

If if t = 0, then d = 0, as well since at t=0 the train is at the station

At t = 1 then d = 110.

From equation (1) d can be replaced by f(t) then we have

f(t) = 110t----------------eqn(2)

Now we replace d by f (t), because d = f t):

f(t) = 120t

Therefore, The function that relates the distance traveled d to the time is f(t) = 120t

5 0

3 years ago

A software company decided to conduct a survey on customer satisfaction. Out of 564 customers who participated in the online sur

nikklg [1K]

Answer:

$z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8$

$p_v =2*P(z$

Step-by-step explanation:

Information given

n=564 represent the sample selected

X=51 represent the number of people who rated the overall services as poor

$\hat p=\frac{51}{564}=0.0904$ estimated proportion of people who rated the overall services as poor

$p_o=0.1$ is the value to compare

z would represent the statistic

Hypothsis to analyze

We want to analyze if the proportion of customers who would rate the overall car rental services as poor is 0.1, so then the system of hypothesis are:

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

The statistic for a one z test for a proportion is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8$

And the p value since we have a bilateral test is given b:

$p_v =2*P(z$

3 0

4 years ago

Gus is making a Chilli recipe that calls 3 parts beans to five parts ground beef .if he is using 8 cups of ground beef for a big

masya89 [10]

First you need to find the percent equivalent to that of the ratio. The ratio is 3:5. From there you would take the 3, and divide it by 5. 3/5=0.6. Apply that to the information that you are given: 8(0.6)=4.8.

4 0

3 years ago

What is the answer to this solution. -7r−4≥ 4r+2

tia_tia [17]

Answer:

The solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

$-7r-4\ge \:4r+2$

Add 4 to both sides

$-7r-4+4\ge \:4r+2+4$

Simplify

$-7r\ge \:4r+6$

Subtract 4r from both sides

$-7r-4r\ge \:4r+6-4r$

Simplify

$-11r\ge \:6$

Multiply both sides by -1 (reverses the inequality)

$\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)$

Simplify

$11r\le \:-6$

Divide both sides by 11

$\frac{11r}{11}\le \frac{-6}{11}$

Simplify

$r\le \:-\frac{6}{11}$

Therefore, the solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

7 0

3 years ago

Which expression is equivalent to 7a^2b + 10a^2b^2 + 14a^2b^3?

vladimir1956 [14]

7a^2b + 10a^2b^2 + 14a^2b^3 =
a^2b (7 + 10b + 14b^2) <==

3 0

4 years ago

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￼￼I NEED HELP ON THIS PROBLEM QUICKLY PLEASE AND THANK YOU

I NEED HELP ON THIS PROBLEM QUICKLY PLEASE AND THANK YOU