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DiKsa [7]
2 years ago
14

Which expression is equivalent to 3/ x^5y

20" id="TexFormula1" title=" \sqrt[3]{ {x}^{5}y } " alt=" \sqrt[3]{ {x}^{5}y } " align="absmiddle" class="latex-formula">
​

Mathematics
2 answers:
noname [10]2 years ago
7 0

Answer:

{x}^{ \frac{5}{3} }  {y}^{ \frac{1}{3} }

Step-by-step explanation:

A cube root is equivalent to the power of 1/3, so by taking the powers of the exponents and multiplying them by 1/3, you get your answer.

Serga [27]2 years ago
5 0

Answer:

\sqrt[3]{x^5 \  y } = (x^5 y)^\frac{1}{3}  = x^{ \frac{5}{3}} \ y^ { \frac{1}{3}}

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What is the volume of the following rectangular prism?<br> 21/2 units <br> 8/3 units
xeze [42]

Answer:

28 units³

Step-by-step explanation:

The volume (V) of the prism is calculated as

V = Al ( A is the area of end face and l is the length )

Here A = \frac{21}{2} and l = \frac{8}{3} , thus

V = \frac{21}{2} × \frac{8}{3} ( cancel 21 and 3 by 3 and 2 and 8 by 2 )

= \frac{7}{1} × \frac{4}{1} = 7 × 4 = 28 units³

5 0
3 years ago
What is 100 * 100 the anser is 1000
Volgvan

Answer:

yes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLEASE DO NUMBER 1 SHOW WORK TOO PLEASE
kirill [66]

Answer:

A) False - not a right angle

B) True - it is a right angle

C) True - it is a right angle

D) False-not a right angle

Step-by-step explanation:

A) a*a+b*b=c*c (Asquared+Bsquared=C squared)

    2*2+ 3*3 = 4*4

   4+9=16

    13 does not equal 16

B) 5*5+12*12=13+13

  25+144=169

  169=169 - True

C) 3*3+4*4=5*5

    9+16=25

     25=25 (True)

D) 4+ Root of 3 = Root of 19

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6 0
3 years ago
Boris is ordering supplies for his company. He ordered 20 boxes of pencils and 32 boxes of pens. What is the ratio of boxes of p
Allisa [31]
\frac{boxes \ of \ pens}{boxes \ of \ pencils}=\frac{32}{20}=\frac{8 \times 4}{5 \times 4}=\boxed{\frac{8}{5}} \Leftarrow A
6 0
3 years ago
Read 2 more answers
Helpppppppppppppppppppppp..... .......<br><br><br>​
morpeh [17]

Answer:

{ \sf{( \sec \theta -  \csc \theta)(1 +  \tan \theta +  \cot \theta) }} \\  = { \sf{( \sec \theta +  \tan \theta \sec \theta +  \cot  \theta \sec  \theta) - ( \csc  \theta -   \csc \theta \tan  \theta -  \csc \theta \cot  \theta)}} \\  = { \sf{( \sec \theta +  \sec \theta \tan  \theta +  \csc  \theta) - (  \csc  \theta -  \sec \theta -  \csc  \theta \cot   \theta)}} \\  = { \sf{ \sec  \theta \tan  \theta +  \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}

3 0
2 years ago
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