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DiKsa [7]
2 years ago
14

Which expression is equivalent to 3/ x^5y

20" id="TexFormula1" title=" \sqrt[3]{ {x}^{5}y } " alt=" \sqrt[3]{ {x}^{5}y } " align="absmiddle" class="latex-formula">
​

Mathematics
2 answers:
noname [10]2 years ago
7 0

Answer:

{x}^{ \frac{5}{3} }  {y}^{ \frac{1}{3} }

Step-by-step explanation:

A cube root is equivalent to the power of 1/3, so by taking the powers of the exponents and multiplying them by 1/3, you get your answer.

Serga [27]2 years ago
5 0

Answer:

\sqrt[3]{x^5 \  y } = (x^5 y)^\frac{1}{3}  = x^{ \frac{5}{3}} \ y^ { \frac{1}{3}}

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Find two possible factors for the estimated product 1600
TEA [102]
Two factors that give a product of 1600 can be 80 × 20
4 0
3 years ago
Please I need help and I give brainliest thank you!!
Marysya12 [62]

Answer:

i believe it is x=4

Step-by-step explanation:

10x+7=12x-1

7=12x−1−10x

8=2x

divide

x=4

6 0
3 years ago
There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g
-BARSIC- [3]

The inequality \mathrm{b} \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }} gives the least number of buses, b, needed for the trip. The least number of buses is 9

<u>Solution:</u>

Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.  

Each bus can seat a maximum of 48.  

We have to find which inequality gives the least number of buses, b, needed for the trip?

Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers

<em><u>The number of buses required “b” is given as:</u></em>

\text { (b) } \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}

\text { So, number of buses required } \geq \frac{432}{48}

Number of buses required ≥  9 buses.

But least number will be 9 from the above inequality.

Hence, the inequality \mathrm{b} \geq \frac{\text {total number of travelers}}{\text {capacity of each bus}} gives least count of busses and least count is 9.

6 0
3 years ago
An object has a mass of 225 g and a volume of 15 cm3.<br> Find the density of the object in g/cm3
ioda

Answer:

D=m/v

=225g/15cm^3

=15g/cm^3

Step-by-step explanation:

The formula for calculating density is: density=mass/volume.

after collecting data you will see that all the data is already in the question and there's no need to convert any units. Divide the mass by the volume and you'll have the density in g/cm^3

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2 years ago
Find the midpoint of NP⎯⎯⎯⎯⎯ given N(2a, 2b) and P(2a, 0).
geniusboy [140]

Answer:

(2a, b )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ \frac{1}{2}(x₁ + x₂ ), \frac{1}{2}(y₁ + y₂ ) ]

Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus

midpoint = [ \frac{1}{2}(2a + 2a), \frac{1}{2}(2b + 0 ) ] = (2a, b )

4 0
3 years ago
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