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defon
3 years ago
5

6sin^2theta = 7- 5costhetaplease include all steps thank you ~ will give branliest !!​

Mathematics
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

6sin^2(x) = 7 - 5cos(x)

6(1 - cos^2(x)) = 7 - 5cos(x)

6 - 6cos^2(x) = 7 - 5cos(x)

6cos^2(x) + 5cos(x) -1 = 0

(6cos(x) - 1)(cos(x) + 1) = 0

cos(x) = 1/6

x = arccos(1/6)

x = 1.40334825 + 2k*pi, 4.87983706 + 2k*pi

cos(x) = -1

x = pi + 2k*pi

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You can say it in word form or expanded form
7 0
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An athlete ran 42000 m in 2 hour 20 minutes.- 140min
bekas [8.4K]
A) 42,000m divided by 2 1/3 = 18,000m divide by 1000m to get km = 18km/hr

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4 0
3 years ago
13x=-21-6y and -8x=36+6y
IgorLugansk [536]

Answer:

x=3\\y=-10

Step-by-step explanation:

13x=-21-6y\\-8x=36+6y

Let's take one of the equations and solve for x. I'll take the first one.

13x=-21-6y

Divide by 13.

x=\frac{-21-6y}{13}

Now replace x in the second equation.

-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y

Distribute -8

\frac{168+48y}{13}=36+6y

Break down the fraction.

\frac{168}{13}+\frac{48}{13}y=36+6y

Subtract \frac{168}{13}

\frac{48}{13}y=36+6y-\frac{168}{13}

Subtract 6y

\frac{48}{13}y-6y=36-\frac{168}{13}

Combine like terms;

\frac{48-13*6}{13}y=\frac{36*13-168}{13}

Solve;

\frac{48-78}{13}y=\frac{468-168}{13}

Keep solving;

\frac{-30}{13}y=\frac{300}{13}

Multiply by the negative reciprocal of the fraction next to y.

(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

y=-10

After having found y, replace it in any of the equations to find x.

13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3

6 0
3 years ago
Read 2 more answers
Please help ASAP work and answer please please
tiny-mole [99]

Answers:

8. 12x+3= 27

move 3 to the other side , sign changes from +3 to -3

12x+3-3=27-3

12x= 24

divide by 12 for both sides

12x/12=24/12

x= 2

9. 6(y-10)=42

mutiply the bracket by 6

(6)(y)(6)(-10)= 6y-60

6y-60= 42

move -60 to the other side, sign changes from -60 to +60

6y-60+60=42+60

6y=102

divide by 6

6y/6=102/6

y=17

10. 9x-2=4x+13

move +4x to the other side

9x-4x-2= 4x-4x+13

5x-2= 13

5x-2+2= 13+2

5x= 15

divide by 5 for both sides

5x/5= 15/5

x= 3

11. 4/3y+5/2y= 1

find the common denominator for both of the fractions which is 6.

Mutiply by 2 for 4/3y .

4(2)/3(2)y=8/6y

Mutiply by 3 for 5/2y

5(3)/2(3y)= 15/6y

8/6y+15/6y= 23/6y

23/6y= 1

Mutiply both sides by 6/23

23/6y(6/23)= 1 (6/23)

Cross out 6 and 6 , divide by 6 and then becomes 1.

Cross out 23 and 23, divide by 23 and then becomes 1.

1*1*y=y

y= 6/23

5 0
3 years ago
What is the area of the regular pentagon below?
wolverine [178]

Answer:

<em><u>2</u></em><em><u>1</u></em><em><u>y</u></em><em><u>d</u></em><em><u>^</u></em><em><u>2</u></em>

Step-by-step explanation:

join the centre to all the vertex,

since this figure is of regular pentagon, it's will form 5 equal triangle of equal area!

now area of one such triangle is

1/2 ×base ×height

=1/2 ×3.5x2.4 (yd^2)

=4.2 yd^2

now the pentagon is sum of 5 such equal triangle,so it's are will be

5×4.2 (yd^2)

=21 yd^2

✌️:)

7 0
3 years ago
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