Question

6sin^2theta = 7- 5costhetaplease include all steps thank you ~ will give branliest !!​

Answer 1

Answer:

6sin^2(x) = 7 - 5cos(x)

6(1 - cos^2(x)) = 7 - 5cos(x)

6 - 6cos^2(x) = 7 - 5cos(x)

6cos^2(x) + 5cos(x) -1 = 0

(6cos(x) - 1)(cos(x) + 1) = 0

cos(x) = 1/6

x = arccos(1/6)

x = 1.40334825 + 2k*pi, 4.87983706 + 2k*pi

cos(x) = -1

x = pi + 2k*pi