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Fynjy0 [20]
3 years ago
7

7.Show that quadrilateral FGHJ is a trapezoid, but is not a parallelogram.

Mathematics
1 answer:
Fantom [35]3 years ago
6 0

Answer:

Line FJ is -3/1, while Line GH is 3/-2

Step-by-step explanation:

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Suppose a special discount makes the price of Nike air max shoes 10% lower. As result, there is a 20% increase in the quantity d
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It is evident from the problem statement that an overall price reduction of Nike air max shoes will lead to an increase in the demand for the shoe.

In Economics,  the relationship between price and demand is stated as follows <em>"If all other factors remain equal, the higher the price of a good, the </em><em>fewer</em><em> people will </em><em>demand</em><em> that </em><em>good</em><em>. In other words, the </em><em>higher</em><em> the price, the </em><em>lower</em><em> the </em><em>quantity</em><em> demanded and vice versa."</em>

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In all, the Law of Demand tells us that if more people want to buy something, given a limited supply, the price of that thing will be bid higher, also of the price of something is low the demand will be high.

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5 0
2 years ago
What is 10 x 10?
abruzzese [7]

Answer:

100

Step-by-step explanation:

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4 0
3 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
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MariettaO [177]

Answer:

Similarity: sinusoidal function has the same general shape as a sine or cosine function.      Differences: y = sin x and y = cos x

Step-by-step explanation:

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