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Fynjy0 [20]
2 years ago
7

7.Show that quadrilateral FGHJ is a trapezoid, but is not a parallelogram.

Mathematics
1 answer:
Fantom [35]2 years ago
6 0

Answer:

Line FJ is -3/1, while Line GH is 3/-2

Step-by-step explanation:

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HELP ASAP 10 POINTSSSS
dlinn [17]
Answer:
Y= -4 :)

Steps:
Apply rule
-y + 3 = 7
Subtract 3 from both sides
-y + 3 - 3 = 7 - 3
Simplify
-y = 4
Divide both sides by -1
-y/-1 = 4/-1
Simplify
y = -4

7 0
2 years ago
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What is number 315,962,004 write in words ​
solmaris [256]

Answer:

three hundred  fifteen million nine hundred sixty two thousand four

Step-by-step explanation:

5 0
2 years ago
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When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
What is the solution for: 10n^2+n^2+16
ivanzaharov [21]

The solution is n= <u>+</u> 4i/√11

Step-by-step explanation:

step 1: 10n^2+n^2+16=0

step 2: 11n^2+16=0

step 3: 11n^2= -16

step 4: n^2= -16/11

step 5: taking square root on both sides,

            n= √(-16)/√11 (square root of a negative number is a <u>complex term</u> 'i')

            n= <u>+</u> 4i/√11

3 0
3 years ago
A system of equations is given below:
My name is Ann [436]
Solving by substitution:

y = 4x - 3 

2x + 7y = 41

Let us substitute the first equation y = 4x - 3  into the second.

2x + 7y = 41

2x + 7(y = 4x -3) = 41

2x + 7(4x -3) = 41

So that's the third option.

I hope this helps.
4 0
3 years ago
Read 2 more answers
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