1-Find an equation of the plane.
The plane that passes through (8,0,-1)
and contains the line x=4-4t , y=1+5t , z=4+2t
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2-Find an equation of the plane.
The plane that passes through the point (-2,2,2)
and contains the line of intersection of the planes
x+y-z=3 and 3x-y+5z=5
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3-Find an equation of the plane.
The plane that passes through the line of intersection of the planes x-z=1 and y+2z=2
and is perpendicular to the plane x+y-4z=3
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4-Where does the line through
<span>(1, 0, 1) and (4,-2,3)intersect the plane</span><span>x + y + z = 8 ?</span>
(7y² + 6xy) - (-2xy + 3)
⇒ (-1 * -2xy) + (-1 * 3) = 2xy - 3
7y² + 6xy + 2xy - 3
7y² + 8xy - 3 Choice B.
Answer:
i rlly dont want to make you wrong cause i feel lik im wrong but i got all of them as cant be sides of triangles
Step-by-step explanation:
i did use a calculator tho
<h2><em>Answer:</em></h2><h2><em>=</em><em>12</em></h2><h2><em>12step</em><em> </em><em>by step explanation:</em></h2><h2><em>=</em><em>solution:</em></h2><h2><em>solution: area of gym= 144</em></h2><h2><em>solution: area of gym= 144we know that,</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L²</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L²</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144)</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144) or, 12= L </em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144) or, 12= L therefore, L = 12 </em></h2>
