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3 years ago

6

Can you please mildly explain this with the answer.

1 answer:

kow [346]3 years ago

3 0

$\bf \begin{cases} f(x)=&5x-1\\ f(-3)=&5(-3)-1\\ f(-3)=&-15-1\\ f(-3)=&-16 \end{cases}\qquad \begin{cases} g(x)=&2x^2+1\\ g(-3)=&2(-3)^2+1\\ g(-3)=&2(-3)(-3)+1\\ g(-3)=&2(9)+1\\ g(-3)=&18+1\\ g(-3)=&19 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (f\times g)(-3)\implies f(-3)\times g(-3)\implies (-16)(19)\implies -304$

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zaharov [31]

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3 years ago

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xxMikexx [17]

Answer:

Step-by-step explanation:

Amplitude is twice the coefficent of the sine function. In this case, $2*2=4$

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Phase shift, is how much you sum or subctract from x inside the sine, in this case $\pi$ .

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3 years ago

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Vanyuwa [196]

Answer:

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Step-by-step explanation:

A equation is given to us , which is ,

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$\longrightarrow alog\ m = log \ m^a$

Applying this to LHS , we have ;

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Now the bases of logarithm on LHS and RHS is same . On comparing , we have ;

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Put square root on both sides,

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Simplify ,

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This is the required answer.

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2 years ago

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3 years ago

Read 2 more answers

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disa [49]

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3 years ago