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3 years ago

Help me with this yes im lazy 2 pages thats it.

Mathematics

1 answer:

valentinak56 [21]3 years ago

5 0

Answer:

2.) $\frac{1}{4}/3=\frac{1}{4}*\frac{1}{3}=\frac{1}{12}$ s yes she is correct

3.) $\frac{1}{5}*\frac{1}{7}$

4.)C $\frac{1}{5}/2= \frac{2}{5}$ ,D $\frac{1}{12}/5=\frac{1}{60}$ ,E

6.) $\frac{1}{8}/3=\frac{1}{24}$

Step-by-step explanation:

im not very good at word problems so i didnt do the secnd page sorry

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You want to test the effect of light on the distribution of Artemia in your 35cm long testing chamber. If you measure the light

Dvinal [7]

Answer:

64.3 lumens

Step-by-step explanation:

Data provided in the question:

Length of the testing chamber = 35 cm

Light at one end = 10 lumens

Light at other end = 200 lumens

now,

since the variation is linear,

therefore, the gradient of the variation

= $\frac{200-10}{35}$

= 5.43

also,

the darkest end is the end with 10 lumens

therefore,

The lumens at 10 cm from the darkest end

= 10 + 5.43(10)

= 10 + 54.3

= 64.3 lumens

6 0

3 years ago

2 questions in the 2 pictures and then im done thank you

Tamiku [17]

Answer:

Hey there!

For the first question we use the triangle area formula: 1/2bh, or 1/2(8)(5). This gives us 20 for the area.

For the second question we get a trapezoid, since the cross section does not pass through the vertex.

Hope this helps :)

3 0

3 years ago

How many digits are written when 1000 to the power of 2015 is expressed as a numeral?

PtichkaEL [24]

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

$1000^{2015}$

We have to find the number of digits ,

So,

$1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}$

Since we know that

$10^n\text{ has n+1 number of digits }$

so,

$10^{6045}\text{ has 6046 number of digits }$

Hence, there are 6046 digits will be written on expansion upto 2015th power.

6 0

2 years ago

Prachi was 5 kilometers east of her home when she began driving farther east at 70 kilometers per hour. Let f(n) be Prachi's dis

Yanka [14]

Answer:

Prachi was 5 kilometers east of her home when she began driving farther east at 70 kilometers per hour.

Let f(n) be Prachi's distance from her home at the beginning of the nth hour of her drive.

f is an arithmetic sequence.

Write an explicit formula for the sequence.

f(n) = 70n + 5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (

Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

The correct equation is

$y+1=\sqrt{-2y-3}$

Solve for y

squared both sides

$(y+1)^2=(-2y-3)$

$(y^2+2y+1)=(-2y-3)$

$y^2+2y+1+2y+3=0$

$y^2+4y+4=0$

$(y+2)(y+2)=0$

$y=-2$

Verify

substitute the value of y in the original expression

$-2+1=\sqrt{-2(-2)-3}$

$-1=1$ ----> is not true

therefore

There are no true solutions to the equation.

4 0

3 years ago