Answer: "11 and 12" .
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11² = 121 ;
12² = 144;
140 falls between 121 and 144 .
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Hmm, alright
not necicarily in that order
probblity=desired outcomes/total possible outcomes
so
4 suits
so the first card is either a 9,10, jack, queen or king of any suit
5*4=20 (4 suits) so 20/52 is probability
now we gots to pick the same suit
now we has 4 cards out of the 51 left that we want
4/51
now we has 3/50
then 2/49
then 1/48
multiply them all together
20/52 times 4/51 times 3/50 times 2/49 times 1/48=480/311875200=1/649740
probablity is 1 in 649740 or about 0.000153% chance
Answer:
53/66
Explanation:
We can use complementary counting to find the probability of picking the outcomes we don't want, and then subtracting that from the whole. The outcomes we don't want are PPPP and PPPN.
Probability of picking PPPP: 5/11 * 4/10 * 3/9 * 2/8 = 120/7920 = 1/66
Probability of picking PPPN: 5/11 * 4/10 * 3/9 * 6/8 = 360/7290 = 3/66
We can arrange PPPN in four different ways (PPPN, PPNP, PNPP, NPPP) so we need to multiply by 4, giving 12/66.
The total of these two probabilities is 13/66. Subtracting from 66/66, the answer is 53/66.
The numbers are 21 and 28.
Answer:
420 unique combinations
Step-by-step explanation:
Simply multiply:
2 * 5 * 6
There are 2 choices for the first set, and 5 choices for the second set. Each of the 2 choices from the first set can be combined with each of the 5 choices from the second set. So, there are 2 times 5 combinations from the first and second sets.