The product of (n2-6n+3) and -4 is
2 answers:
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Answer:
B
Step-by-step explanation:
One good way to look at this is to graph both polynomials, as shown in the picture. A tip to help graph is to factor it out and work from there. For example, in x²+14x+48, we can gather that (x+6)(x+8) is the same thing, and it is easier to then graph it. Similarly, for x²+12x+36, we can factor it out as (x+6)² .
When x²+12x+36 approaches 6, it is getting really close to 0, but it stays positive. When x²+14x+48 approaches 6 from the negative side, it is also getting close to 0, but it's negative. When x²+14x+48 approaches 6 from the positive side, it is positive.
Therefore, on the negative side, there is one positive and one negative (dividing a negative by a positive is negative, and a positive by a negative is also negative) , and on the positive side, there are two positives, forming one answer.The answer is therefore B
For question 1 you need to find the sqared values of the hypotenuse, which has a length of 15, and leg b, which has a length of 12. This gives you a hypotenuse of 225 and a leg which is 144. Subtract your given leg squared from your hypotenuse squared (aka 225-144). This leaves you with 81. Now find the square root of this, which is 9.
For question 2 you need to find the squared value of legs a and b. Leg a has an initial length of 6, which squared is 36. The same applies for leg b. Now add 36 to 36 to get 72. All you have to do is find the square root of that to have your answer. Since 72 isn't a perfect square, just simplify the root to 3 root 8, aka
For question 3, repeat the process used in question 1. The square of a square root is the original number (ex: the sqare root of 3 squared is 3). Subtract 7 from 19 to get 12. 12 isn't a perfect square, so simplify the root. You should end up with 2 root 3, aka
For question 4 you must find the sqared value of a, b, and c. The sum of the sqared values of a and b is equal to the squared value of c. If c is 10 and a and b are both x, then the formula is
or
Next, simplify this by first dividing by 2 on each side. You are then left with x squared equals 50. Simplify the root to 5 root 2, aka
For question 5 you need to find the squared value of 47 and 25. This leaves you a hypotenuse of 2209 and a width of 625. Subtract 625 from 2209. This leaves you with 1584. Find the sqare root of this to find your length. Since it isn't a perfect square, simplify the root to get 12 root 11, aka
I hope this helps clear things up for you!
For question 2 you need to find the squared value of legs a and b. Leg a has an initial length of 6, which squared is 36. The same applies for leg b. Now add 36 to 36 to get 72. All you have to do is find the square root of that to have your answer. Since 72 isn't a perfect square, just simplify the root to 3 root 8, aka
For question 3, repeat the process used in question 1. The square of a square root is the original number (ex: the sqare root of 3 squared is 3). Subtract 7 from 19 to get 12. 12 isn't a perfect square, so simplify the root. You should end up with 2 root 3, aka
For question 4 you must find the sqared value of a, b, and c. The sum of the sqared values of a and b is equal to the squared value of c. If c is 10 and a and b are both x, then the formula is
or
Next, simplify this by first dividing by 2 on each side. You are then left with x squared equals 50. Simplify the root to 5 root 2, aka
For question 5 you need to find the squared value of 47 and 25. This leaves you a hypotenuse of 2209 and a width of 625. Subtract 625 from 2209. This leaves you with 1584. Find the sqare root of this to find your length. Since it isn't a perfect square, simplify the root to get 12 root 11, aka
I hope this helps clear things up for you!