The domain is the set of x-values: {-3, 0, 3}.
The range is the set of y-values: {-6, 0, 6}.
The appropriate choice is ...
a. domain: {-3, 0, 3}, range: {-6, 0, 6}
Answer:
y = √(4x - 8) - 3
Step-by-step explanation:
y = 1/4(x + 3)² + 2
To find the inverse, switch the places of the x and y.
x = 1/4(y + 3)² + 2
Solve for y.
x - 2 = (1/4(y + 3)² + 2) - 2
x - 2 = 1/4(y + 3)²
4(x - 2) = 4(1/4(y + 3)²)
4x - 8 = (y + 3)²
√(4x - 8) = √((y + 3)²)
√(4x - 8) = y + 3
√(4x - 8) - 3 = (y + 3) - 3
√(4x - 8) - 3 = y
y = √(4x - 8) - 3
Subtract 24 from both sides.
z + 24 = 10
- 24 -24
z = -14
First,multiply the -2 by everything in the brackets
so that's, -6x-(b-4x)+(x+6b)
then combine like terms
that's -6x-(7b-3x) which is
-3x-7b I believe
The coins differ in value by 5¢, so swapping the numbers of them will change the value by 5¢ for each unit difference in the numbers of coins. Since
40¢ = 8 * 5¢
there must be 8 more dimes than nickels.
There are (22 +8)/2 = 15 dimes and 7 nickels.
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You could write some equations for this problem. Let n, d represent numbers of nickels and dimes.
.. n +d = 22
.. 10d +5n - (10n +5d) = 40 . . . . . . . cents
.. 5(d -n) = 40 . . . . . . . . . . . . . . . . . . reversing the coin count changes the total by 5 cents for each unit of difference (d -n), as stated above.
.. d -n = 8 . . . . . . . . . . . . . . . . . . . . . . divide the preceding equation by 5
Adding this last equation to the first gives
.. 2d = 22 +8
.. d = 30/2 = 15
.. n = 22 -15 = 7
There are 15 dimes and 7 nickels.
