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Natalka [10]
3 years ago
12

? Answer this question

Mathematics
1 answer:
finlep [7]3 years ago
5 0

Answer:

B,because it says he wants to have

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Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

6 0
3 years ago
Read 2 more answers
Plz help fast will mark the brainiest!!!
sergejj [24]

Answer:

627,638,540

Step-by-step explanation:

3 0
3 years ago
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The sum of three consecutive numbers is -12. Find the sum of the integers?
777dan777 [17]

Answer: -3, -4, -5 are the integers

Step-by-step explanation: I don't get what you mean in this problem. You said the sum was -12 but then you are asking for the sum again? Do you want the integers? If so they are -3 -4 and -5 and if you want the sum then it is -12

I hope this helps and brainliest would be appreciated

3 0
3 years ago
A square has an area of 196 in^2.What is the length of the side of the square?
Liula [17]

Answer: 9,216

Step-by-step explanation:

6 0
3 years ago
Write the ratios for sin A and cos A. Not drawn to scale sinA= 24/10, cosA = 10/26 sinA= 24/26, cosA = 10/24
vagabundo [1.1K]

To find the values of trigonometric functions, we can use the acronym SOHCAHTOA, which stands for:

\begin{gathered} \sin\theta=\frac{opposite}{hypotenue} \\  \\ \cos\theta=\frac{adjacent}{hypotenuse} \\  \\ \tan\theta=\frac{opposite}{adjacent} \end{gathered}

Because we are only looking for sin A and cos A, we'll use SOH and CAH. Remember that the positions are relative to angle A. So side BC would be the opposite and side AC would be the adjacent sides.

\begin{gathered} \sin A=\frac{24}{26}\text{ }or\text{ }\frac{12}{13} \\  \\ cosA=\frac{10}{26}\text{ }or\text{ }\frac{5}{13} \end{gathered}

The answer is the third option, sin A = 24/26, cos A = 10/26.

8 0
2 years ago
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