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givi [52]
3 years ago
13

You have 22 coins, dimes and nickels. If the number of dimes and nickels were reversed, you would have $0.40 less than you actua

lly have. How many dimes and nickels do you have?
Mathematics
1 answer:
fenix001 [56]3 years ago
4 0
The coins differ in value by 5¢, so swapping the numbers of them will change the value by 5¢ for each unit difference in the numbers of coins. Since
40¢ = 8 * 5¢
there must be 8 more dimes than nickels.

There are (22 +8)/2 = 15 dimes and 7 nickels.

_____
You could write some equations for this problem. Let n, d represent numbers of nickels and dimes.
.. n +d = 22
.. 10d +5n - (10n +5d) = 40 . . . . . . . cents
.. 5(d -n) = 40 . . . . . . . . . . . . . . . . . . reversing the coin count changes the total by 5 cents for each unit of difference (d -n), as stated above.
.. d -n = 8 . . . . . . . . . . . . . . . . . . . . . . divide the preceding equation by 5
Adding this last equation to the first gives
.. 2d = 22 +8
.. d = 30/2 = 15
.. n = 22 -15 = 7
There are 15 dimes and 7 nickels.
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Aneli [31]

Answer: Hello your question is incomplete below is the missing part

Which of the following statements about Hannah’s claim is supported by the interval?

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B) Hannah is likely to be incorrect because 9 is not contained in the interval.

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 D)The probability that Hannah is correct is 0.01 because 9 is not contained in the interval.

 E)Hannah is likely to be correct because the difference in the sample means (18.6−14.4=4.2)(18.6−14.4=4.2) is contained in the interval.

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Step-by-step explanation:

The statement that is supported by the interval in Hannah's claim is that

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