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givi [52]
3 years ago
13

You have 22 coins, dimes and nickels. If the number of dimes and nickels were reversed, you would have $0.40 less than you actua

lly have. How many dimes and nickels do you have?
Mathematics
1 answer:
fenix001 [56]3 years ago
4 0
The coins differ in value by 5¢, so swapping the numbers of them will change the value by 5¢ for each unit difference in the numbers of coins. Since
40¢ = 8 * 5¢
there must be 8 more dimes than nickels.

There are (22 +8)/2 = 15 dimes and 7 nickels.

_____
You could write some equations for this problem. Let n, d represent numbers of nickels and dimes.
.. n +d = 22
.. 10d +5n - (10n +5d) = 40 . . . . . . . cents
.. 5(d -n) = 40 . . . . . . . . . . . . . . . . . . reversing the coin count changes the total by 5 cents for each unit of difference (d -n), as stated above.
.. d -n = 8 . . . . . . . . . . . . . . . . . . . . . . divide the preceding equation by 5
Adding this last equation to the first gives
.. 2d = 22 +8
.. d = 30/2 = 15
.. n = 22 -15 = 7
There are 15 dimes and 7 nickels.
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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<u>Trigonometry</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Find </u><em><u>x</u></em>

  1. Substitute:                                        tan28° = 8/x
  2. Multiply <em>x </em>on both sides:                 xtan28° = 8
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  4. Evaluate:                                          x = 15.0458
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